Do I need both? If I operate IR2110 with 12 volt?
I was talking about the max voltage which will be available at the Transformer output. Say, input voltage is 12v, trans ratio is 34; so, output voltage=12*34=408goldsmith said:
As i can remember it's input circuitry is cmos ! so 5 volts can be considered as zero ! not one ! . so both of them are required !
Who told this ? don't forget that the out put filter should be LC filter ( at least 2nd order and butterworth ) so if the load be higher than normalized impedance of that filter , it can increase the voltage nearby some kilo volts ! is that reasonable ? or when you have overload ! it will decrease ! so you will need feed back from 2nd section tot he first section ! hence your out put voltage should be a bit more than that to create ability of voltage compensation ! by fed path !
My topology is Bridge. Could you please tell a little more on DS and 2Vm? After filtering the converter output, the voltage will be 325v.goldsmith said:
Okay, understood
Yet to design filter as you suggested to make converter part first. For feedback design, I've considered that there is a inverter and the output of the inverter is sine wave. As the inverter terminal voltage is needed to make nearly constant at any load condition, feedback has been taken from there. Here I'm attaching the block diagram of the total inverter system (12v DC to 230v AC). Please check and suggest if there is any mistake.goldsmith said:
Take a look at here , please :
Thanks...Hi sam
Take a look at here , please :
Will it be so much variable compare to the voltage at converter output?
This is Modified SPWM https://www.edaboard.com/threads/260091/. Does it seem to be nearer to three level inverter? Dear Goldsmith, generating such waveform should not be complected to me using microcontroller. :smile:
Hi sam
I know it is pretty simple to create that waveform . i have designed many inverters based on differentiating SPWM , until now . most important issue will be select a proper stage for power stage . to obtain this waveform . ( you will have at least 4 choice ! ) .
It would be better if you could please tell a little more...
Certainly ! you can create two SPWM with messages out of phase together and them get each section to an arm of an H bridge ! and thus the out put wave before filtering will be exactly as you expected !
I see , an i know you want learn each thing complete ! it is pretty good and i believe that you will earn success in this process ! ( with hope to the G-O-D )
i told you the best way for feed back in this case is a rectified feed back . and about two filters i think you are referring to the out put power filters before your load ? right ? if yes , each differential SPWM inverter will need two filter to create enough simultaneously thus mathematically both signals will be the same thus subtract of them will be zero but you will have -vsin/2 and + vsin/2 that will consequence , Vsin !
Sam , do you know what is the meaning behind words " high frequency link inverter " ? the process that i have told you for many times called high frequency link inverter ( first section with DC /DC converter and a transformer ( link , here ) and a simple SPWM . it will have low THD too ( you can be sure about lower than 0.1 percent if you correctly and carefully design it ! but as you decided to use a three level SPWM ,
Sam , listen carefully ! the waveform that you need can't be achieved with a simple H bridge ! it will be a bit difference and it is kind of multilevel inverter ! ( three level ) . i told you the simplest way but you told me you want to design it ! and i told you i will help you ! because you are interested in three level method !
Of course ! a rectifier will create a little delay ! and a filter will create another delay too . and this path will affect the first stage it means one stage will have another delay too ! . but in your aim it is not important !
Dear sam,
I think you didn't pay attention to things that i have told ! do you know how will be the behavior of a butterworth filter ? and do you know what will happen if the value of load will be higher or lower than normalized impedance of that filter ??! i think you don't know it ! hence you will need a closed loop .
My understanding is - one filter is for 230v, 50Hz output another one is for rectification and filtration of 230v AC to be used as feedback. Am I right now?
Yes, understood. I want to make an Inverter with lowest possible THD along with highest possible efficiency. :smile: Please suggest...
Understood the delay issue. What is impact of such delay and where it is important?
You will have two filter for your special H bridge . and then an auxiliary filter ( low power filter ) for feedback path after rectification the fed signal .
thus this method is ok .
No ! why you have thought this ? just an H bridge ! but you will have two SPWM . with different messages . and then not of each other ( inverted of each other . ) and then a dead time creation ! and then two mosfet driver . you will have right H side and L side and Left H side and L side . right H side will be SPWM A and right L side will be the inverted signal of SPWMA . and left section : H side SPWMB and L side inverted SPWM B . but don't forget that dead time is most important thing in these inverters .
In AC Current sources with high frequency and in transmitters ! and more other things !
Hi goldsmith,
Let me open the words ! for out put stage you will have a butter worth LC 2nd order filter . to separate message signal from SPWM . this filter will have a normalized impedance . but your load isn't constant . thus it can increase the out put or decrease it . so instability is for this stage not first stage ! but first stage can compensate this problem ! i hope you got the idea .
