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it showed some 19.76Volts!
What does it mean?? why this large voltage spike??
It is possible for your LC tank oscillations to build to such a volt level. (As shown by simulations earlier in this thread.)
Your antenna will need a certain ACV level, in order to broadcast. I don't know how high the voltage must be.
I saw an old-timer state that the crucial thing is to make the antenna resonate to your transmitting frequency. This means tuning the antenna.
You want to get standing waves within the antenna. That is when photons are emitted most efficiently from the wire.
19V is OK for inductive load. Transistor 2N3866 can survive up tp 30V Vce0.
Your diode detector already has coupling capacitor and you can measure RF voltages at any point without adding capacitor in series with detector. About potential difference on output we can talk only when we know the output power of amplifier and for that amplifier must be properly tuned. Assuming your amplifier will be able to deliver 250mW power to 50 Ohm load then it is easy to calculate output RF voltage.
Talking of some voltage means that output power is very low. At 50mW power your reading should be over 1V.
First try to tune amplifier. You can use detector and tune stages for max reading.
Just one important remark on your circuit. At least one component in LC tank must be adjustable usually C (trimmer capacitor) or you will not be able to tune amplifier to work. The same is valid for output filter where coupling output capacitor and inductor has to be adjustable.
Sir what is this ACV??
how am i gonna calculate the output power from this potential difference??
It looks like you did not understood.
Nothing wrong - it means there is RF present at that point. If you were measuring the output voltage AT THE ANTENNA CONNECTION you should add the extra load resistor across the input to simulate the real antenna being there. Without it you may get a false high or low reading because the output network can work like a transformer, stepping the voltage down or up. For other places in the circuit you don't want the resistor so it presents a higher impedance and resistance.
As pointed out by others, the output stages have no bias except that provided by the signal itself. If you make the collector tuned circuits tunable with a variable capacitor you can adjust their resonance to 'peak' the signal level to the next stage. As more bias is produced the current through the transistor will increase so you can monitor it to find the best tuning setting. I will urge caution though, when you tune several circuits in an amplifier to the same frequency, the chances of instability are greatly increased. This is why you often see each stage of an amplifier in it's own screened box, it helps to stop them interacting with each other.
Brian.
Your diode detector already has coupling capacitor and you can measure RF voltages at any point without adding capacitor in series with detector. About potential difference on output we can talk only when we know the output power of amplifier and for that amplifier must be properly tuned. Assuming your amplifier will be able to deliver 250mW power to 50 Ohm load then it is easy to calculate output RF voltage.
Talking of some voltage means that output power is very low. At 50mW power your reading should be over 1V.
First try to tune amplifier. You can use detector and tune stages for max reading.
It is very crude but it should work. Check the value of the capacitor at the collector of Q3, you show 100pF, should it be 100nF?
Also double check the value of the capacitor in the base of Q1, it sets the 'squegging' rate of the detector, 4u7 seems too high to me, check it shouldn't be 4n7.
Incidentally, radiation resistance in a receiving antenna has no meaning!
Brian.
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