FreshmanNewbie
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In this Application Note, Section 4.2 GFCI Fault Detection and Test, page 14, can someone tell me the working of the circuit.
Unable to understand it.
Unable to understand it.
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Thank you. In the second line of the paragraph, it is mentioned " A discharge path", can you tell me what is the discharge path? 2. Is the signal in GFCI+, an AC signal? 3. Why is there a diode in output of both the op-amps?You read the application note, so what part do you not understand ?
Regards, Dana.
Thank you. In the second line of the paragraph, it is mentioned " A discharge path", can you tell me what is the discharge path? 2. Is the signal in GFCI+, an AC signal? 3. Why is there a diode in output of both the op-amps?Hi,
Same circuit as in your last thread.
Working of this protective circuit
Below is a circuit which I found that is used for Protective Earth Neutral detection. The PEN_ON comes from MCU and PEN_dET does to an MCU. P20, is a current transformer. Can someone explain me the working of this circuit and why it is required? This is an application of an EV charger...www.edaboard.com
Klaus
Thank you. In the second line of the paragraph, it is mentioned " A discharge path", can you tell me what is the discharge path? 2. Is the signal in GFCI+, an AC signal? 3. Why is there a diode in output of both the op-amps?First opamp is peak detector with gain of -100. Second opamp is comparator with, for some unknown reason, a diode on the output.
Its a half-wave rectifier, not full-wave (still, maybe a peak detector, depending on how you look at it)
First OpAmp acting as a FW rectifier.
View attachment 183408
The discahrge path is for C3 back thru R59, R10, R14,.
GFCI - https://home.howstuffworks.com/question117.htm
Regards, Dana.
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Something like this :
View attachment 183411
Regards, Dana.
Not with those component values. It's got a gain of 100 in the negative direction. A gain of 1 in the positive direction.The ap note seems to indicate, rightfully, its FW :
Regards, Dana.