do you mean the charge controler circuitIt is not advisable to make 3.5Kva inverter using 24vDC , you are dealing with almost 146 A, which is too high. Battery voltage should be at least 60Vdc.
Because you are using a transformer of 146A capacity if the charging is not controlled using some circuit it will surely heat up. please post the charging circuit.
regards ani
replace it with what other value?Dear sam1145,
I have also faced this kind of situation.In inverter mode it was working fine but in charging mode both channels start heating
(sometimes it burnt).I have checked sg3524 osc. was off but there was about 0.3v present at the gate of FET's. Changing
the driver transistor solved my problem (it was a leakage current ). In your case replacing Q13 & Q14 may solve the problem.
Thanks
You can test weather a charging circuit is necessary or not by the following experiment.do you mean the charge controler circuit
because there no other circuit apart from those ones you up there
thanks Tahmid,i used the multimeter and its reading -0.205v and when reverse the props its +0.205vCheck the outputs of the driver stage (to MOSFET gate) to ensure that no gate drive signals are generated.
It is best to observe the signal on an oscilloscope. You can also use a voltmeter to see if the outputs show a steady 0V.
thanks Tahmid,i used the multimeter and its reading -0.205v and when reverse the props its +0.205vCheck the outputs of the driver stage (to MOSFET gate) to ensure that no gate drive signals are generated.
It is best to observe the signal on an oscilloscope. You can also use a voltmeter to see if the outputs show a steady 0V.
the relay is it VAC powered?
All FETs are shown connected wrong way. This must only be in schematic drawn otherwise inverter won't be working. Similarly R1 And R2 be 100 ohm like other gate resistors.
When mains is restored, a relay connects mains input to mains output after disconnecting inverter output and also disconnects DC from control circuit.
the relay is it VAC powered?
All FETs are shown connected wrong way. This must only be in schematic drawn otherwise inverter won't be working. Similarly R1 And R2 be 100 ohm like other gate resistors.
When mains is restored, a relay connects mains input to mains output after disconnecting inverter output and also disconnects DC from control circuit.
like what value of resistor ?One more thing is that the outputs of the SG3524 should be pulled down. Either connect pull-down resistors from pins 11 and 14 to ground or connect pull-down resistors from bases of Q13 and Q14 to ground.
3.5Kva*746=2611 watts.can someone post the a detailed transformer winding formula for 3.5kva/24vdc inverter
@pnjbtr: haw did you get 746 and 211 up there?3.5Kva*746=2611 watts.
Small transformer,s efficiency 90%.
So,we need 2611+211=2872 watts transformer.
I am adding 10% losses(211w) in total wattage.
We need 10 square inch bobbin size,may be 2.5*4 or 2*5.
2.5 inch core have much stack height,and is suitable for your transformer.
Now we need to select wire gauge.
2611\24=load on battery and secondary winding,108.7Amp.
For almost 110 Amp,we should select SWG,8 bifilar ( 2 wires of swg,8 parallel).
Now primary winding wire should be,
2611/220=11.8 amp.
For primary swg 15 is suitable in 2.5*4 bobbin.
17.5+17.5 turns are for secondary.
And 176,192,200 turns are for primary.
200 turns for 250v.
192 turns for 240v.
176 turns for 220v(charging loop).
I suggest you reduce battery size and make with 48v dc.
Sorry it is calculation mistake original value is 261.@pnjbtr: how did you get 746 and 211 up there?
@pnjbtr: thanksSorry it is calculation mistake original value is 261.
261w is 10% losses in iron and copper wire
When we calculate power units.
We use terms of watts,Kw.
Va and Kva.
In Ac power calculation, Va is less then watts.
And 1kva =746 watts.
For detail see https://www.rapidtables.com/electric/electric_power.htm
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