Hello Dear white.1588
Here is some rules for design :
1- AV*Beta should become a bit more than one to start and keep the oscillations.
2-the AV= c17/c18
3- Beta = c18/c17
( my mean by av=c17/c18 , is that you should try to design the AV of your amplifier about it . )
I'm a little confused about those equation based one what AV and Beta are equal to then AV*Beta=1 all the time; since AV and Beta are reciprical fractions
C19 at 10MHz give a reactance of .0159Ohms, which is a short essentially (thought that was purpose of that cap?).
Forgot to mention my bias current Ic=1mA
The resistor network I made based on the fact that the base voltage is 1.5V (from R4 drop) + .7 (forward bias diode drop base to emitter) = 2.2V. I've heard that the rule of thumb for picking (to neglect the base current) R3 is R3<10*R4-----> R3<15K so I picked R3 to be 7k. From that the current going through the bias branch is then 2.2V/7Kohm=314uA. Based on the approximation that the base current is approximately zero; I solved for R1 from (12V-2.2V)/R1=314uA, R1=31K. I thought all those approximations were the right way to bias the bjt?
So are we talking like 1ohm or so for the resistance in the inductor?
Would the DC blocking cap at the top of the LC network just go to ground? But wouldn't that effect the resonant freq?
The bias current is only 1mA, so maybe bias for a bit more
Yes, that's what I meant with "far off from a reasonable dimensioning". The loop gain is rather high, resulting in a distorted waveform. But there are also aspects like suitable LC impedance level.but i think if c1 and c2 be unequal with together , it will be better ? isn't it ?
Yes, that's what I meant with "far off from a reasonable dimensioning". The loop gain is rather high, resulting in a distorted waveform. But there are also aspects like suitable LC impedance level.
Dear jesica
Hi
Do you want just the value of components ? don't you want learn how to design ?
Best Wishes
Goldsmith
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