- Joined
- Jan 22, 2008
- Messages
- 53,065
- Helped
- 14,790
- Reputation
- 29,867
- Reaction score
- 14,282
- Trophy points
- 1,393
- Location
- Bochum, Germany
- Activity points
- 300,876
Maybe I'm relying too much on the original specification that talks about DDS and 1 A sinoidal current.It may be straightforward but not necessary simple or easily made stable with an inductive load. Since he stated that a square-wave would be okay, I showed a simple circuit that generates a current limited output and is stable with an arbitrary inductive load.
The circuit I posted uses 100% emitter feedback so is relatively insensitive to transistor gain variations and nonlinearities.....................................
A discrete transistor driver isn't bad as such. I would prefer internal feedback per stage instead of being stuck to transistor current gain variations and nonlinearity.
As shown, I would describe the circuit as switched resistor source. Hardly better then a push-pull dríver with 5 ohm series resistor. To make the emitter feedback work as a current source, there must be a lower voltage drop, e.g. 1V across the resistor and a respectively modified base control circuit.The circuit I posted uses 100% emitter feedback.
But you can imagine a shunt resistor (say 1 ohm) to sense the current?
There should be someone like a supervisor to help with the prerequisites of your software work. (Hopefully it's not over his head as well)
Maybe I'm relying too much on the original specification that talks about DDS and 1 A sinoidal current.
I think that the stability problems can be easily overcome, but yes a certain analog design knowledge will be required.
Instead of feedback, current control through software might be an option, requiring a current measurement however.
A discrete transistor driver isn't bad as such. I would prefer internal feedback per stage instead of being stuck to transistor current gain variations and nonlinearity.
Feedback is now from amplifier output, keeping the the coil voltage constant. Instead feedback can be made from a shunt resistor, keeping the voltage across the resistor respectively the coil current constant.I am already taking the line back to negative input. What would an extra 1 ohm resistor do?
Feedback is now from amplifier output, keeping the the coil voltage constant. Instead feedback can be made from a shunt resistor, keeping the voltage across the resistor respectively the coil current constant.
Your are correct. My brain was in neutral. :-| Scratch my circuit as shown.As shown, I would describe the circuit as switched resistor source. Hardly better then a push-pull dríver with 5 ohm series resistor. To make the emitter feedback work as a current source, there must be a lower voltage drop, e.g. 1V across the resistor and a respectively modified base control circuit.
If the small oscillations noted on the output voltage (but not showing in the output current) are a problem than a compensation capacitor of about 1nF across R1 should help.
We use cookies and similar technologies for the following purposes:
Do you accept cookies and these technologies?
We use cookies and similar technologies for the following purposes:
Do you accept cookies and these technologies?