REQ: TX radiation Power related to the time slots

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Rayengine

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Dear All,

Assume that we know the peak radiation power and also the number of time-slot, how can we relate to the average power?


BR
Rayengine
 

When you integrate radiated power in 1 sec interval you will get average power. Rule of thumb for systems with on/of regime: Pa=Pmax*duty_cycle

Regards
D.
 

Debeli said:
When you integrate radiated power in 1 sec interval you will get average power. Rule of thumb for systems with on/of regime: Pa=Pmax*duty_cycle

Regards
D.
Click to expand...

Thanks your reply. Your answer is quite common to what I predicted. However, one expert in the field told me that

The Average power = Peak power - Antenna gain-10 log(1/x) where x is duty cycle.

I want to know if there any reference related to this equation.

BR
 

The relation I quoted is you can also find in "Radar Encyclopedia" that can be found here in download section. The values are all in natural dimensions i.e. Watts, not dBW or dBms. If your power is in dBs than the relation is Pa=Pmax+10*log(duty_cycle). It is the same like in your expression log(1/x) = -log(x)

For my sense, involving antena gain in the way the expert said means that the peak power is radiated (EIRP) and average power is the power at the antenna port. The relation can be applied if you want to determine average power that that amplifier delivers to the antenna if you now the peak EIRP (it is for me uncommon).

Maybe it helped
Regards
 

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