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pthoppay said:Hi,
Signal Power(S)= (no.of bits)* Eb
N= No* B(bandwidth of signal)
So
S/N= (n*Eb)/(No*B)
Regards,
Thoppay
gurpreet said:can anybody tell me the exact relationship between SNR and Eb/No?
gurpreet
amihomo said:Hi
In an M-ary system :
Es/N0 (dB)=Eb/N0(dB) +log2(k) ,where k=code rate×log2(M)
(when coding is not used ,code rate is equal to 1)
Es/N0(dB)=10log10(Tsymbol/Tsampling) + SNR(dB)
hence , the realtion between Eb/No and SNR is given by :
Eb/N0(dB)=SNR(dB) + 10log10(Tsymbol/Tsampling) - log2(k)
regards