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You test our patience to the limits!
Try this: walk from one end of your room to the other and time how long it takes to do it. From that can you calculate what time of day it is?
An RC network does NOT have a frequency, it does not produce any repetitive signal which you can measure. If you don't believe us, connect your 1K and 0.01uF capacitor is series across the input of your frequency counter and see what it tells you. Try then in parallel and see if it makes any difference.
What it produces is DELAY in voltage change because the resistor limits the flow of current into and out of the capacitor. To measure the delay you have to look at the signal entering the RC network and the signal leaving it and see how much time difference there is between them. A frequency counter is useless for that, you need an oscilloscope, ideally one with a dual trace. You look at both signals and count the time divisions on the X-axis to see how much time difference there is between the input and output waveforms.
I will say this: if you are going to the trouble of measuring time constants like that, it would be quicker to remove the resistor and capacitor from circuit and test them conventionally and it would almost certainly be more cost effective to simply replace them altogether.
Brian.
Try this: walk from one end of your room to the other and time how long it takes to do it. From that can you calculate what time of day it is?
An RC network does NOT have a frequency, it does not produce any repetitive signal which you can measure. If you don't believe us, connect your 1K and 0.01uF capacitor is series across the input of your frequency counter and see what it tells you. Try then in parallel and see if it makes any difference.
What it produces is DELAY in voltage change because the resistor limits the flow of current into and out of the capacitor. To measure the delay you have to look at the signal entering the RC network and the signal leaving it and see how much time difference there is between them. A frequency counter is useless for that, you need an oscilloscope, ideally one with a dual trace. You look at both signals and count the time divisions on the X-axis to see how much time difference there is between the input and output waveforms.
I will say this: if you are going to the trouble of measuring time constants like that, it would be quicker to remove the resistor and capacitor from circuit and test them conventionally and it would almost certainly be more cost effective to simply replace them altogether.
Brian.