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Nobody knows why the low-pass function has been combined with a voltage divider, although the shunt voltage is already small. This further complicates to acquire the filtered voltage without interferences.I worked it out but found the gain to be Load_R/(Load_R+R1)! So for Big loads the filter isnt very effective? Is that a correct observation?
Apparently the problem has been handled by the revised measurement circuit in post #9. It could be further improved by placing another capacitor parallel to the 100k resistor.