properly using LM4040C41LPR

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yefj

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Hello,I have the following components called LM4040C41ILPR, it has 3 pins.
given the schematics below , how can know what each leg represents?
Thanks.

LM4040C41ILPR | DigiKey Electronics

Order today, ships today. LM4040C41ILPR – Shunt Voltage Reference IC Fixed 4.096V V ±0.5% 15 mA TO-92-3 from Texas Instruments. Pricing and Availability on millions of electronic components from Digi-Key Electronics.
www.digikey.com

 

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Hello Dana,two questions:
1.do you reccomend to keep pin 3 floating?
2.why the "anode" is the minus sign while the say that pin3 is ground?
What kind of diode is that?
where do i put the high voltage where the lower voltage potential(GND)?
Thanks.
 
Last edited:

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READ THE DATASHEET!!!

Stop being willfully ignorant.

The title of the datasheet tells you exactly “what kind of diode it is”

YOU post the section of the datasheet that says ‘pin 3 must float’ and then you ask “do you recommend to keep pin 3 floating?”.

What is your problem?
 

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Hello,So If I understand correctly I need to put the device as shown below.
I think that the series resistor will act as current limitor also.
from the datashet they say 15mA should flow threw it.
I dont have ltspice model.
given the datasheet formula below.
Vs=12V Vz=4V What is I_L and I_z?
I_z=15mA
(Vs-Vz)/Rs=(8V)/Rs=I_total
I am confused how can I find the proper Rs needed in this situation.
Thanks.



 
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Do you even know how to read? All the answers are in the datasheet.

I can explain it to you, but I can’t understand it for you.
 

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Hello, there is a logical problem ,In the table they say Anode pin 2 should be connecte to ground while pin 1 is the voltage.
But as you can see in the little arrows they say that the minus is on pin 1 so its contradicting because in the table they say that the lower voltage potential should be on pin 2.
Thanks.
 

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Table is in error, as you show earlier this is correct connection





Anode is - or ground side. The above are correct.
 

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Hello Dana , I have connected the diode as shown in the lab below.
I have a real weird phenomena, My out is 12V instead of 4V, but when i check the diode voltage with multimeter between 1 and two i get 1V.
What could cause this?
Thanks.
 

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Pinout is bottom view of package, you dont have accidental reverse connections ? Unless
this also is another error in datasheet.
 
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danadakk said:
Table is in error, as you show earlier this is correct connection

View attachment 195185

View attachment 195186

Anode is - or ground side. The above are correct.
Click to expand...
There is nothing wrong with the table : pin 2 is the Anode, FOR THE DBZ PACKAGE ONLY.
--- Updated ---

This is my last response to you, I’m not wasting my time any more with any of your ludicrous posts.

“Out” is the voltage between 2 and ground. Ground is pin1. Therefore, out is the voltage between pins 2 and 1, yet you say you measure 1V between 2 and 1, and 12V at Out.
 
Last edited:

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Hello Dana,Yes you are probably correct .
The third leg is substrate leg.
What do you think did i burn the device?
Is there a way I could check using multimeter if this device is still alive?
Thanks.
 

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If you used the 1K no should be OK.

Just hook it up and give it a go.



Why did you number your pic reverse order ? This is looking at bottom pins pointing at you,
the package away from you....


 

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