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The input impedance for the impedance matching network will be 50 ohms, right?
A diode automatically adjusts its internal resistance, so that current and voltage obey its particular equation. Suppose you get 1 mA and 0.4V. Therefore the diode presents 400 ohms.
Suppose its 15mA and 0.5V. Then diode resistance is 33 ohms.
To improve efficiency your antenna ought to be a size and shape which picks up sufficient rf, so that it generates voltage high enough to overcome diode threshold voltage.