light emitting diode control differ controls

[Okada]

Bulb is 12V 6W. 500 mA

 

[KlausST]

Hi,

this doesn´t answer the question about supply voltage.
All the schematics show 5V only.

Klaus

 

[venkates2218]

does gates input will work based on PWM pulse..?

 

[Okada]

Yes, You can input PWM to AND gate inputs. Check the frequency that the gate can handle.

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@KlausST

He has a few more threads and in one he has mentioned that he is using 12V battery to drive the 12V 6W Lamp.

 

[venkates2218]

okada
Can we use ULN2003A instead of 2N222A..?

 

[Okada]

Yes, you can use connect two outputs of ULN2003A to one side of Lamp and another side of Lamp to +12.0V. Short both bases of channel 1 and 2 and drive it through a PIC TTL 5V pin but use base resistor as mentioned in the datasheet. Two channels in parallel can handle 500 mA current. Don't use single channel. Single channel rating is 500 mA and your current is also 500 mA.

 

[venkates2218]

if we short two channel means..it can handle 1A..?
because each channel can having capacity of 500mA

 

[Okada]

Yes. If you need to sink more current then you have to short more channels.

 

[KlausST]

Hi,

Yes, you can use connect two outputs of ULN2003A to one side of Lamp and another side of Lamp to +12.0V. Short both bases of channel 1 and 2 and drive it through a PIC TTL 5V pin but use base resistor as mentioned in the datasheet. Two channels in parallel can handle 500 mA current. Don't use single channel. Single channel rating is 500 mA and your current is also 500 mA.

I recommend to read the datasheet before you give answers.

A light bulb may have up to ten times cold current (peak, switch ON current)

ULN2003 is rated for 600mA peak current per channel.
--> Two channels can´t handle the peak current.

If you drive a 500mA (not taking care of peak current) load with two ULN2003 channels then expect at least 70°C junction temperature. A bit less case temperature. Is this what you want?

Klaus

 

[Easyrider83]

This is so stupid! Just look at Figure 7. Maximum and Typical Saturated VCE vs Output Current in manual. There will be almost 2W of heat!

 

[Okada]

He doesn't want to use Mosfet and the solution is to use paralleled darlington pairs and dissipate whatever heat is generated with a heatsink.

 

[venkates2218]

This is so stupid! Just look at Figure 7. Maximum and Typical Saturated VCE vs Output Current in manual. There will be almost 2W of heat!

sorry i cant understand it....
whether it is suitable or not..?

 

[Easyrider83]

It is bipolar transistors. You looking at absolut maximum current. No point to parallel it due to nature of biporal transistors. Current will not be splitted equal. Anyway, Okada, stop giving bad advices.

 

[venkates2218]

He doesn't want to use Mosfet and the solution is to use paralleled darlington pairs and dissipate whatever heat is generated with a heatsink.

thanks for your support
no like that okada
i'm thinking on cost of the project also...IRF540 is suitable for it..?

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IRF540 is suitable for it..?

 

[Easyrider83]

IRF540 is suitable for it..?

You choosed it randomly?

 

[KlausST]

Hi,

He doesn't want to use Mosfet

..and he refuses to give an explanation why.

MOSFET is simple to use, good available, cheap, small, about no disspated heat, about no drive current. I can see no drawback.


But the OP is free to accept advice or not...

Klaus

 

[venkates2218]

You choosed it randomly?

this only available in local market near to me
and i think it suitable for our purpose also

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Hi,



..and he refuses to give an explanation why.

MOSFET is simple to use, good available, cheap, small, about no disspated heat, about no drive current. I can see no drawback.


But the OP is free to accept advice or not...

Klaus

i looked for low cost and simply hardware thats why i searched manythings...

ok i will use MOSFET itself....
Is IRF540 is right choice..?

 

[Okada]

I have not analyzed or tested this circuit but you do the calculations.

https://electronics.stackexchange.c...-driver-for-mosfet-irf540-and-microcontroller

You cannot directly drive the IRF540 from 5V or 3.3V MCU output pin. You need a mosfet driver.

 

[andre_luis]

Is IRF540 is right choice..?

Depends on what you're talking about, right choice to immediately solve your problem, or to have a well-sized design ?

 

[Okada]

You can use this scircuit.

https://electronics.stackexchange.c...-driver-for-mosfet-irf540-and-microcontroller

It is providing 12V Vgs to the mosfet. It will work for you.

How many usits are you manufacturing or going to manufacture ? If more than 200 then buy the mosfets which I earlier mentioned from mouser.in