gauravkothari23
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The schematic is OK although I would add a resistor in series with the input. Your problem is the 11N60DM2 which needs as much as 5V on its gate before it STARTS conducting. Ideally you want far more than that to ensure it turns full on .
The simplest modification I can think of is to connect Q5 collector and R2 to 24V and add another transistor at the input to drive Q5 and Q6.
Brian.
Try what I suggested.so why when i switch it faster at 300Khz, the mosfet is not getting OFF and stays ON due to which i am getting continues 24V at the output.
Both of those might work but they would be risky. You might find it works with one MOSFET but not another of the same type. You really need to increase the gate voltage or use a logic level MOSFET.
Try this simple change:
1. remove Q6.
2. connect Q5 emitter to ground,
3. connect Q5 collector to the gate of the MOSFET and a 1K resistor to +24V,
4. connect Q5 base to the 8051 through a 470 Ohm resistor.
The idea is that the 10K resistor holds the MOSFET in hard conduction, current through Q5 when biased from the 8051 pulls the gate voltage close to zero and turns it off.
Beware that if you stop the drive waveform or disconnect the 8051 it will leave the MOSFET in conducting state, if you want to protect against that without other side-effects, connect a 100K resistor from Q5 base to +24V.
Brian.
i am getting continues 24V at the output.
Why without load, now? It's no surprise if you don't have a load ... to get continous straight lineLet me make a point that all this results are without any load
Try what I suggested.
Your problem with higher frequencies is you need more drive current and you are already borderline on having enough available. Don't think of a MOSFET as being a perfect voltage operated switch, it comes close at low frequencies but imagine there is quite a large capacitor between its gate and source pins (think 1nF or more). As the frequency increases, so does the current needed to charge and discharge that capacitance. This is why you usually see a power driver before the MOSFET and most of the common IR2xxx driver ICs are rated at 1A or more output current. It isn't because of the DC switching characteristics of the MOSFET, it is to charge and discharge the gate voltage rapidly to ensure full switching and least time in the partially conducting region where power loss is highest.
Brian.
All I can think of is you have the diode reversed or the coil has such low impedance it appears like a short circuit.
Can you describe the coil please.
Are those resistors really 46 Ohms, it isn't a standard value.
Brian.
Hi,
I can't see why the gate voltage should be 17V only.
Thus I assume the schematics don't show the reality.
Please take some photos of your circuit...including scope connections and ... show the scope pictures
Klaus
Something is wrong there.
I assume the top 'scope trace is gate to SOURCE not drain.
Can you show a photograph of the construction please, all I can think of is you have the source and gate pins swapped.
When you say "I have not connected any coil, all the testings are made without load" I assume you have SOME load on it, even if the coil pins are shorted together, otherwise there can be no drain current.
Brian.
Something is wrong there.
I assume the top 'scope trace is gate to SOURCE not drain.
Can you show a photograph of the construction please, all I can think of is you have the source and gate pins swapped.
When you say "I have not connected any coil, all the testings are made without load" I assume you have SOME load on it, even if the coil pins are shorted together, otherwise there can be no drain current.
Brian.
It's not a problem of the MOSFET. It's the same as with BJTs and relays....i was not aware that MOSFETS do not work properly without load.
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