horttanainen
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There is a four wire connector on the PSU board. It has pins labeled from 1 to 4. On the schematics there are labeled lines (1M2, 2M2, and 3M2) coming from PSU from places like the cathode of D141, D142, and D143. These *M2 labels indicate the pin on the four wire connector socket on the PSU board.By the way, where are you getting these pin designations from???
I did as you asked, but instead of desoldering S492 I cut the wire between S494 and D141.Here's what you must do:
Make sure the PSU is attached to the monitor.
Disconnect one end of S494 (yes, you read correctly) and place the 240V bulb/s in as the dummy load for
the 126V rail on the cathode of D141. As I remember, you had two 240V bulbs. They should be in parallel with
each other when using them.
It seems that the fault lies in the 126 volt rail.At some point in your measurements you should see at least two voltages that should be correct. When that
hapends, then the fault will lie in the rail with the light bulb/s being used as a dummy load.
It seems that the fault lies in the 126 volt rail.
Next step is to remove the horizontal output transistor (TS467) which should be
connected to a largish heatsink.
Measure it to see if it's shorted. You may find an integral diode between the
collector and emitter. It should measure a diode drop one way only.
It's important that you measure it out of circuit, as there's very low ohms between
the base and emitter. Around 4 odd ohms due to R465, S465 and T401.
If the transistor measures OK, then leave it out of circuit, turn the monitor on, then
measure the cathode of D141 again.
If the voltage returns to normal, then TS467is unserviceable and needs replacement.
If the voltage is still low, we need to look elsewhere.
I have good news! TS467 is faulty.
TS467 is a Philips BU508A NPN transistor
Do you want me to check any other components in the meantime?
Yes. I'll get you to check D467 and D468. D467 is used in place of an internal diode to the
horizontal output transistor. It's there to suppress high voltage transients that may occur.
Are there any other components you would like me to check?
How did you know to ask me to check TS467?
I am asking this because my guess would have been any component thats attached to ground and the 125 volt rail, like R494, C494, R469, C469, D468, D467 and so on.
Furthermore, if transistor TS467 would have been fine what component would have you asked me to check next, and why?
At this point there's no specific component that I need you to check, but I would
like you to test the 125 volt rail while the horizontal output transistor is out of circuit.
I'll get you to attach the 240V light globes to D141's cathode and measure the 125 volt
rail to see that it is correct. If it does read correctly, then we know with a very high
certainty that the horizontal output transistor is the only thing wrong with the unit.
I hope that answers your query.
As for C471, it's used for coupling and if that was open circuit, no signal would be able to pass to the scan coils.
A short would allow the monitor to work, though you wouldn't see any symmetry with the picture.
and my apologies for the long wait. I have had practically zero spare time to work on this project in the past weeks.
I attached the light bulbs and the monitor as instructed. I also had D467 out of circuit in addition to TS467. The voltage rail measured correctly as 125.5 volts.
Unfortunately, it seems that the post office lost the replacement for D467 in transit. This means that I have to order a new one and we will have to wait for another week or so.
Huge thank you for the thorough answer! This helps me understand what is going on and why.
While we wait for the post office to try to deliver the replacement for the replacement of D467, I would like to ask you another question: where does the signal, that capacitor C471 couples, originate?
Thanks I got the gist of what's going on of the above description!A pulsed signal originates from Pin 4 of IC402 into TS461, which is the horizontal driver transistor, which amplifies the signal into a transformer which AC couples It to the horizontal output transistor. C471 is there to block any DC, but only allows the AC signal generated to pass to the horizontal coils within the yoke assembly.
It's actually more complicated than the description above, but due to my age, it's been eons since I did any substantial circuit analysis'.
Sorry if i'm not precise.
I hope that it gives you the gist of what's going on.
Could it be that I ordered wrong replacement part for TS467? Left is the original part and right is the replacement.
It looks as though you have the monitor on free run, no signal coming in.
So does anything change when you connect a computer? Does the crt show the entire computer image? Then does the rightmost edge remain dark?
Or is there some other more obvious reason behind the display not centering? To my understanding there is a voltage missing somewhere (or too much voltage).
It looks as though you have the monitor on free run, no signal coming in. This is a default mode of operating. It's not following instructions of any frame length or frame height or frame rate from an incoming video signal.
So does anything change when you connect a computer? Does the crt show the entire computer image? Then does the rightmost edge remain dark?
I ordered the part from europe but apparently the origin of the component is china. The funny thing is that I tried to google the manufacturer prior to ordering this part but I too could not find any manufacturers with this "SH" logo. I think this should have put me off but I could not resist ordering a component with the same initials as me.The big question is; did you order the part from China?
If so, then I'd say that is the problem of TS467 overheating.
Unfortunately China is notorious for producing fake semiconductors. Well below their ratings.
I cannot discern the manufacturer symbol on the new horizontal output transistor. Got to be a clone for sure.
If you did purchase the transistor from China, then you need to go to a reputable spare parts dealer and get
an original.
One other thing, the transistor you obtained shouldn't be an insulated type.
There is a good possibility that there may be a fault with one of the integrated circuits. IC302 to be exact.
What I need you to do is to check the Vcc voltage on IC302. Which is Pin 9 of the IC. It should be around
26 volts.
If you find it OK, then start measuring all the other pins of the IC to determine if any of them are low or
high.
As I've said already you really need a static signal whilst doing those measurements. A pattern generator
would be an ideal signal source, but that isn't practical in this instance.
PIN | Indicated Voltage | Measured Voltage |
1 | 7 | 6.9 |
2 | 1.4 | 1.4 |
3 | 5.5 | 6 |
4 | 2.4 | 2.1 |
5 | 25 | 25.2 |
6 | 15 | 12.7 |
7 | 7.5 | 5.6 |
8 | GND | Did not measure |
9 | 26 | 25.3 |
10 | 1.8 | 2.1 |
11 | 0.24 | 6.1 |
12 | ??? | 21 |
13 | 4.5 | 4.1 |
OK, since your monitor is showing a horizontal shift fault, I got you
to test the wrong IC.
It's IC402 that I need you to check all the voltages on.
I deeply apologise for this.
PIN | Indicated Voltage (on the monitor schematic) | Measured Voltage |
1 | - | 0 |
2 | 0.2 | 0.4 |
3 | 6.4 | 6.9 |
4 | 0.9 | 0.9 |
5 | GND | Did not measure |
6 | 1.6 | 1.5 |
7 | - | 4 |
8 | 6.2 | 6 |
9 | ??? | 1.5 |
10 | 2.8 | 5.4 |
11 | 0.13 | 5.4 |
12 | 0.4 | 5.8 |
13 | ??? | 11.5 |
14 | 6 | 5.8 |
15 | 11.8 | 5.8 |
16 | 6 | 7 |
17 | 4 | 1.9 |
18 | 6 | 5.5 |
By the way, could you please provide a part number for IC402 as well
as the part number for IC302.
Guys just wanna say this thread is superb and helped me a lot as well! I registered to the forum because of it and I am amazed from the amount of knowledge found here!
I wont hijack the thread, maybe when you finish repairing your monitor and I truly hope so - these are beauties, I will then ask why mine has some fade vertical banding on the left side.
Congratulations for your persistance.
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