ian123
Junior Member level 3
[quote}but note that this is the case only when the mosfet is turned on and stays in that state.
so if i had to switch the mosfet on and then keep it switched on say for two secs then the heat dissipation would be 2.43 watts even though the passive load is drawing 3 amps at 300vdc ?
---------- Post added at 17:28 ---------- Previous post was at 17:17 ----------
The 2.43 W calculation is basically correct. There are also other kinds of transistor losses involved, see my post #10.
The 280 W maximum rating is a more theoretical value, that won't be achievable in most cases, e.g. because you can't provide a respective heatsink size.
So apart from the other losses are you saying that only 2.43 watts is dissipated by the mosfets therefore i should be able to have quite a small heatsink say 60mm wide would give me 12degrees per watt therefore the heatsink would go upto say 25 degrees plus ambient temp?
would my reasoning be correct
would this be enough heatsinking for the mosfets???
---------- Post added at 17:39 ---------- Previous post was at 17:28 ----------
The bridge rectifier power dissipation will be in fact twice the value of a single diode. According to a 8A datasheet that I have (KBU8), it's 2*3A*0.9V = 5.4W, resulting in about 100 K temperature rise with 18 K/W thermal resistance.
please explain 100 "K" does this = kelvin or centigrade
1 Kelvin =273.15 degrees celcius then 100 x 273.15 = 27315 degrees centigrade (about the same as a large furnace).
---------- Post added at 17:42 ---------- Previous post was at 17:39 ----------
would the bridge alone need a 12.5 cm heatsink and the mosfets a 6.0 cm heatsink