goodpranoy
Junior Member level 3
- Joined
- Dec 5, 2013
- Messages
- 29
- Helped
- 0
- Reputation
- 0
- Reaction score
- 0
- Trophy points
- 1
- Activity points
- 201
debouncing removes the 0/1/0/1 toggling you get when you move a switch, so the idea is after debouncing you get a single clean 0 -> 1 transition.
after the debouncing i get a constant value right.
i got this code from the net for debouncing.
how can i get a single clean transition from this code?
Code:
LIBRARY ieee;
USE ieee.std_logic_1164.all;
USE ieee.std_logic_unsigned.all;
ENTITY debounce IS
GENERIC(
counter_size : INTEGER := 19); --counter size (19 bits gives 10.5ms with 50MHz clock)
PORT(
clk : IN STD_LOGIC; --input clock
button : IN STD_LOGIC; --input signal to be debounced
result : OUT STD_LOGIC); --debounced signal
END debounce;
ARCHITECTURE logic OF debounce IS
SIGNAL flipflops : STD_LOGIC_VECTOR(1 DOWNTO 0); --input flip flops
SIGNAL counter_set : STD_LOGIC; --sync reset to zero
SIGNAL counter_out : STD_LOGIC_VECTOR(counter_size DOWNTO 0) := (OTHERS => '0'); --counter output
BEGIN
counter_set <= flipflops(0) xor flipflops(1); --determine when to start/reset counter
PROCESS(clk)
BEGIN
IF(clk'EVENT and clk = '1') THEN
flipflops(0) <= button;
flipflops(1) <= flipflops(0);
If(counter_set = '1') THEN --reset counter because input is changing
counter_out <= (OTHERS => '0');
ELSIF(counter_out(counter_size) = '0') THEN --stable input time is not yet met
counter_out <= counter_out + 1;
ELSE --stable input time is met
result <= flipflops(1);
END IF;
END IF;
END PROCESS;
END logic;