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It is WRONG like most circuits on that website.You need to modulate the transmitter.
The TX section of the link below will do the job.
Simple arithmetic shows that the transistor will soon burn out:
1) With a 9V supply and the IR LED has a forward voltage of 1.5V then the current is (9V - 1.5V)/18 ohms= 417mA.
But the maximum allowed current for a BC547 transistor is only 100mA. A 2N4401 transistor has a maximum current of 600mA and should be used.
2) The base resistor is much too high at 10k. With a 9V supply, the output high of the 555 could be only 7V. To properly saturate, the transistor needs a base current 1/10th its collector current. For 42mA, the base resistor value should be (7V - 0.8V)/42mA= 148 ohms, use 150 ohms.
EDIT: Will the IR LED survive 417mA?