Tunelabguy
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OK, let's look at the numbers. The inverter supplies up to 50 Amps. The shunt is 0.001 Ohms. So the maximum shunt voltage is 50 mv. As someone pointed out before, if you want 0.1% accuracy, you need an input offset voltage of less than 50 uv, which is really hard to do in the presence of high power circuits. Also, it is very hard to get a 0.001 Ohm resistor accurate to within 0.1%. That means knowing the resistance to within 0.000001 Ohms. It would take some very careful 4-wire connections to the resistor to accomplish this feat.
A more dependable solution is to raise the value of the shunt resistor. Of course it will have to be a power resistor now, maybe even with a heat sink. But at least you can measure it, control it, connect with it, and do something easy with the voltage generated. A shunt resistor of 0.01 Ohms would dissipate 25 watts, with a maximum shunt voltage of 0.5 volts. If your inverter is supplying power at 230 or 120 volts, it most likely can afford to sacrifice half a volt at full output.
A more dependable solution is to raise the value of the shunt resistor. Of course it will have to be a power resistor now, maybe even with a heat sink. But at least you can measure it, control it, connect with it, and do something easy with the voltage generated. A shunt resistor of 0.01 Ohms would dissipate 25 watts, with a maximum shunt voltage of 0.5 volts. If your inverter is supplying power at 230 or 120 volts, it most likely can afford to sacrifice half a volt at full output.