Working of op-amp in below circuit

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hello,

Here i attached one circuit diagram. Please find it.
Can anyone explain the working of op-amp or in which configuration opamp is used ???

Please help me to understand.
Thank you in advance.

 
Last edited:

It's a somewhat odd circuit.
There's 2.52V on the plus input to offset the output by that amount.
The op amp acts as an inverting amplifier with three feedback circuits.
The series output resistor may be to make the circuit stable with high capacitance output loads, but that's not entirely clear to me.
 

I concur with Crutschow about the output series resistor but it is nevertheless a strange circuit. Without any series input resistor the feedback network may not work anyway, it would rely on the previous stage to allow the gain to be set.

Can you show the circuit around it so it can be seen in context.

Brian.
 

As already explained, the feedback circuit is useless for R2=0.

In addition, the effect of R4 and C2 depends on the OP loop gain and output impedance. I doubt that it has considerable effect with OPA4313. The component values might be copied and pasted from a different OP, or just calculated wrongly.
 

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