Wilkinson Divider Current Density

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If I simulate a Wilkinson Power Divider current density without the isolation resistors, will I get current density minimums at the locations where the isolation resistors belong? I'm running AWR/Microwave Office.

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GE
 

Where is your feed? If you feed from the common port, the structure is symmetric and there is no current through the resistor anyway.
 
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The feed could be from either direction depending on how the divider/combiner is used. If I feed from the divider ports (not common port), I guess that I will need to excite both divider ports in-phase.
 

ge said:
The feed could be from either direction depending on how the divider/combiner is used. If I feed from the divider ports (not common port), I guess that I will need to excite both divider ports in-phase.
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Yes, the resistor is only needed for isolation (asymmetric currents).
 

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