Mar 29, 2015 #1 S shanmei Advanced Member level 1 Joined Jul 26, 2006 Messages 430 Helped 8 Reputation 16 Reaction score 8 Trophy points 1,298 Location USA Visit site Activity points 4,496 From the two inputs, we know the difference voltage is Vin-Vout, after amplifying A, Vout=(Vin-Vout)*A, Vout(1+A)= Vin, so Vout/Vin=1/(1+A). When A is infinite, Vout/Vin=0? it is wrong , why? Thanks.
From the two inputs, we know the difference voltage is Vin-Vout, after amplifying A, Vout=(Vin-Vout)*A, Vout(1+A)= Vin, so Vout/Vin=1/(1+A). When A is infinite, Vout/Vin=0? it is wrong , why? Thanks.
Mar 29, 2015 #2 Dominik Przyborowski Advanced Member level 4 Joined Jun 6, 2013 Messages 1,227 Helped 510 Reputation 1,025 Reaction score 508 Trophy points 1,393 Location Norway Visit site Activity points 9,516 You lost one multiplication by A. The Vo/Vi=1/(1+1/A)
Mar 29, 2015 #3 S shanmei Advanced Member level 1 Joined Jul 26, 2006 Messages 430 Helped 8 Reputation 16 Reaction score 8 Trophy points 1,298 Location USA Visit site Activity points 4,496 Thanks. Dominik Przyborowski.
Mar 30, 2015 #4 Audioguru Advanced Member level 7 Joined Jan 19, 2008 Messages 9,461 Helped 2,152 Reputation 4,304 Reaction score 2,011 Trophy points 1,393 Location Toronto area of Canada Visit site Activity points 59,764 It is obvious that the gain is 1 like a piece of wire.