Could anyone tell me why does this kind of circuit used to bias the non-inverting pin of and inverting amp. As i know it would provide 0.5Vcc to non inverting pin. Can we jus use dividing resistor. Why do this circuit is used often aspecially in power amp circuit ?
Resistor divider will have a higher output impedance. This circuit will have a low output impedance so it will be able to respond faster to changes in output of power amplifier (as this node will be coupled to output). So any changes in utput will affect this bias node also.
Could anyone tell me why does this kind of circuit used to bias the non-inverting pin of and inverting amp. As i know it would provide 0.5Vcc to non inverting pin. Can we jus use dividing resistor. Why do this circuit is used often aspecially in power amp circuit ?
if you use the voltage divider to drive the resistor load, you won't be able to get the voltage 0.5vcc to drive the resitor load, the voltage will drop. But if you use the buffer in between, you can get voltage 0.5vcc to drive the resistor load because the buffer can sink more current and it is a negative feedback, the
output will very stable with low output impedance.