why higher frequencies result in smaller components ?

[desperado1]

higher frequency smaller components

In power electronics using higher frequencies we can reduce the size of components. What's the technical reason behind it ?

 

[dipnirvana]

Well as you increase the frequency , you decrease the switching period and hence more frequently you can store energy hence need a lower inductor (less size) for given power.

 

[desperado1]

Thanks for the reply. Does the same apply to capacitors as well.......

 

[dipnirvana]

with higher frequency , capacitor will go smaller for different reason . Lower size will have lower inductance , hence more effective capacitor

 

[pranam77]

When you use higher frequencies, the wavelenght of the same will be small, and thus the PCB, and the components may be shrinked along with the power consumption. The tracks on the PCB too are required to be designed in small areas. Good luck

 

[jwfan]

High frequency makes the current ripple on inductor and the voltage ripple on capacitor smaller. So, smaller L/C can be used to achieve same ripple.

With high frequency, the control bandwidth can also be pushed to higher frequency, the compensation compensation can be smaller, too.

 

[olanre]

XL(inductive reactance) = 2 pi f L where pi= 3.142(a constant), f=frequency and L=inductor value. From the formula XL=2pifL

L=XL/2pif The more you increase the frequency (f) the less the inductor value and size.

XC=1/2pifC therefore C=capacitance = 1/2pifXC. As in the inductor, the more the frequency (f) increases, the less the capacitance value hence the size of the capacitor.