modern_analog
Newbie level 5
L effect on mismatch
This might sound very basic but here goes
The mismatch depends on WL, or more accurately 1/sqrt(WL). Then why do we need large L. It seems we can get away with small L and large W.
This might sound very basic but here goes
The mismatch depends on WL, or more accurately 1/sqrt(WL). Then why do we need large L. It seems we can get away with small L and large W.