Nov 9, 2011 #1 J John_li Full Member level 5 Joined Aug 6, 2005 Messages 272 Helped 9 Reputation 18 Reaction score 1 Trophy points 1,298 Activity points 2,945 Hi friends, As my attached,any friend can give me a hand?Thanks:-D
Nov 9, 2011 #2 J jpanhalt Advanced Member level 3 Joined Jun 28, 2010 Messages 722 Helped 216 Reputation 442 Reaction score 217 Trophy points 1,323 Activity points 6,948 If you look at the sources as resistors in parallel, then R(single) = 6R(total) E/I = R(total) Substitution to solve for R(single) E/I = 6R(total) = R(single) QED. Of course, some assumptions are made that are not explicitly stated in the question. John
If you look at the sources as resistors in parallel, then R(single) = 6R(total) E/I = R(total) Substitution to solve for R(single) E/I = 6R(total) = R(single) QED. Of course, some assumptions are made that are not explicitly stated in the question. John
Nov 12, 2011 #3 J John_li Full Member level 5 Joined Aug 6, 2005 Messages 272 Helped 9 Reputation 18 Reaction score 1 Trophy points 1,298 Activity points 2,945 Thank you for help/