Re: Single Loop Circuit
No!
One engineer helped me with explanation, and here is how it looks like:
in all the cases the following relations must hold:
-1.8V3 + 40i + V3 = 0, i = 0.02V3, if the dependent voltage source is supplying power(if the 90 V source supplies power then the current direction is such that the dependent voltage source must also supply power)
-1.8V3 - 40i + V3 = 0, i = -0.02V3, if the dependent voltage source is absorbing power.
a) Well, in the first case the 90V source is supplying the power so the
current is going out the positive terminal....so:
-90V + 10i + 20V - V3 = 0
i = (70V + V3)/10, and from above i = 0.02V3, so:
(70V + V3)/10 = 0.02V3
V3 = -87.5V
i = -87.5 * 0.02 = -1.75A
P = IV = -87.5 * (-1.75) = 153.125W, But the problem said that P = 180W, so "a" has No Solution
"b" is similiar.
c) The dependent source generages 100 W....so from the first equation , i = 0.02V3, and P = IV. so: 100W = 0.02V3*V3, V3 = sqrt(100/0.02) = 70.71v
i = 0.02 * 70.71v = 1.414A
The 90 V supply must also supply power by virtue of the current direction
so from part a:
i = (V3 + 70)/10 = (70.71 + 70)/10 = 14.071A
But 14.071A is not equal to 1.414A, so... "c" has no Solution
similiar with "d"
that was an explanation.
thanks all!