It has no isolation from the mains input, so anyone touching the output can experience a lethal shock.So why is it deemed a no-go'er?
Thanks, yes, that would be the makers of the chip (power integrations)...they wont give us any technical reason, despite repeatedly asking them.--> ask those people who "deem it to be a no goer".
Thanks, but one 1kV diode will be fine IMHO.There are two things worth considering. Firstly,
using only one input high-voltage rectifier diode is easily damaged, and at least
two need to be connected in series (the answer can be found in the diode specification book).
In addition, when LNK3209 is damaged, the load will withstand high voltage and be damaged.
It is recommended to increase the power of the 3209 power supply circuit as an output while
also supplying power to the 3209.
What?Thanks, yes, that would be the makers of the chip
If the effective value of the input AC voltage is Urms, then its peak value is 1.414 * Urms;Thanks, yes, that would be the makers of the chip (power integrations)...they wont give us any technical reason, despite repeatedly asking them.
They recomended we do a buck boost design instead, giving a -24V, 17W output.....and i guess they intend us to deal with that to get our wanted output.........but they didnt say why a buckboost......i have a funny feeling that in their labs, they have tried it in Buck topology, and it didnt work, but maybe they dont know why(?)......not sure really. They also recomend a flyback instead, but again, dont say why not the Buck.
Thanks, but one 1kV diode will be fine IMHO.
If LNK3209 is damaged, then so be it....the fuse will blow.......theres no reason why it should become damaged in large occurrence.
We supply power to the LNK3209 as per the datasheet and app note AN-70.....it bascially gets a bootstrapped supply from the 24v output.....(we havent built it yet but thats what we intend)
Thanks, yes thats right, but that just means we need a rectifier with high enough V rating, and we have that.If the effective value of the input AC voltage is Urms, then its peak value is 1.414 * Urms;
Therefore, the output voltage of a unidirectional half wave rectification circuit with capacitive filtering is Uo=1.414 * Urms;
In this way, when the input voltage is the maximum value of negative half cycle, which is -1.414 * Urms,
The voltage at both ends of this diode is equal to 1.414 * Urms - (-1.414 * Urms)=2.828 * Urms.
For example, if the input power supply is 220V rms AC mains, the maximum voltage at both ends of the diode for half wave rectification is:
2.828 * 220=622.16V. 240 * 1.1 * 2.828=746.59V 1N4007 (RMS)=700V
Thanks, ill submit the analysis if you wish.....but i believe , by inspection, you can see that such a buck converter is well within the bounds of possibility for this chip, according to its datasheet....specially since we have loads of blown air over the cctry all the time.What am I missing? Post #1 doesn't refer to any critical analysis of the shown design. Is it a riddle?
Thanks, Power Integrations (various of their apps engineers) advise us not to do Buck for 24v 17w.....they do not say why. They instead just tell us to do a buckboost for -24v, or a flyback....but not Buck.The question is who said it's a bad circuit and why they think so?
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