what is the taylor series expansion of this ?

[tomshack]

what is the taylor series expansion of this ?

1 ÷ (1+(wb)²)

 

[pmonon]

which one is the indep. variable, w or b?

 

[tomshack]

which one is the indep. variable, w or b?

b

 

[E-design]

1+b².w²+[(w.b)²]²

 

[tomshack]

1+b².w²+[(w.b)²]²

i think this is not the right answer.........

 

[pmonon]

if b is the indep. variable and w is const.,

1/(1+(wb)2) = 1/(1+(wδ)2) - {2wδ/(1+(wδ)2 )-2}(b-δ) - ........ + …..

see the attachment for further...

 

[tomshack]

if b is the indep. variable and w is const.,

1/(1+(wb)2) = 1/(1+(wδ)2) - {2wδ/(1+(wδ)2 )-2}(b-δ) - ........ + …..

see the attachment for further...

thank u my friend but i have the result but i dont know the solution .........the question is 9.th in pdf file

 

[tomshack]

ok guys i solved my problem thnk u for all

 

[E-design]

Care to let us in on the solution?

 

[tomshack]

Care to let us in on the solution?

sure the taylor expansion of 1/1+x² = Σ ((-1)^n ) (x^2*n) n=0:finite wb=a in the question ....sorry e desing i didnt tell u wb is a constant at the first post...thank u for all your helps