boylesg
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I don't agree about "unusual". A 555 circuit with feedback from output instead of DISCHG pin can be already found as 50 % duty cycle oscillator in the LMC555 datasheet. The variant with diodes and variable duty cycle is at least frequently used.
The 'output' and 'discharge' pins carry identical signals but have different electrical characteristics so it is posible to swap them in some circumstances.
I agree with FvM that some flavors of 555 are different to others, the worst case of this I found was a type that 'froze' it's ouput when reset was applied rather than turning the output off. It caused me considerable problems once in a HV power unit where it fed the gate of a MOSFET in an inverter which had it's output fed back to the reset pin to give crude voltage stabilization (it was a pre-regulator circuit). Instead of shutting the FET off when the output voltage was reached, it randomly left it turned on and drew enough current to overheat it. I can't remember the manufacturer but in most 555s the reset pin directly connects to the output flip-flop, in this one it gated the input to it instead.
Brian.
The 'output' and 'discharge' pins carry identical signals ...
What puzzles me is why two potentiometers are used. Their relative values change the on/off ratio and their combined values set the frequency (as well as the 'sub' capacitor). Personally, I would have gone for a more conventional astable circuit where the frequency and ratio are less dependant on each other. I'm also a little puzzled by the antenna circuit. If I understand it, the 555 does not set the output frequency, that is decided by the feedback, presumably from the arc to the antenna which I'm guessing is primarily controlled by the inductance of the output transformer. The 555 is there either to allow some degree of control over it, or to provide the initial 'kick' to start it running.
I'm also puzzled as to why two high current FET drivers are used to drive a transformer, I would think it makes more sense to drive the FETs directly as the output is isolated anyway. I can see the potential mains power isolation issue. Also, why use an inverting and a non-inverting FET driver when their inputs come from an inverter where both polarities are available anyway. It isn't wrong as it is, just curiously designed.
Brian.
I'm also puzzled as to why two high current FET drivers are used to drive a transformer, I would think it makes more sense to drive the FETs directly as the output is isolated anyway. I can see the potential mains power isolation issue. Also, why use an inverting and a non-inverting FET driver when their inputs come from an inverter where both polarities are available anyway. It isn't wrong as it is, just curiously designed.
Brian.
I understand the implications of damage if the FETs die but the vast majority of inverters and FET power switches used direct drive without any problems and using the driver transformer like that increases costs and reduces efficiency. In fact, direct drive to the FETs probably makes them more reliable than using a transformer anyway. My point about the driver ICs is simply that it seems odd (but not wrong) to use two different drivers when the signal feeding them comes from an inverter IC anyway. It usually works out cheaper to use the same IC type and feed the inputs from pins 3 & 4 of the 74HC14 feeding it.
Brian.
I'm not convinced an antenna is the best way to do this but given the high impeadance at the HC14 input pin, I would suggest putting a resistor of say 10K in series with the antenna. Keep the two diodes on the IC side of the resistor. The classic protection method would be to wire a neon lamp between the antenna wire and ground as well. It will do nothing until about 90V is across it then it will flash and conduct the HV away.
Brian.
Putting fuses in parallel isn't a good way to test for current! A far better way is to place a low value resistor (suggest 0.1 Ohm) in series with the supply and measure the voltage across it, preferably with an oscilloscope.
Bear in mind that the average FET current is being drawn from your mains supply. I'm not sure where you are but it's rare for a wall outlet to be rated at 25A so something else will likely blow before the FETs or fuses.
Brian.
I've never heard of neon lamps being used in a camping lamp before so I can't comment on that. The type you want are small glass tubes, about 10mm long and 5mm diameter with two wires leaving at one end. Inside you can see two parallel electrodes which glow orange when it's lit up. They are commonly used as power indicators in wall sockets or on some mains powered appliances, connected across the AC with a series resistor of 150K or so to limit their current. Electrically, because the electrodes don't touch and neon gas isn't conductive, they are open circuits and as such will have no effect on the antenna signal whatsoever. The way they protect is to do with a property of neon gas that allows it to ionize easily. When the voltage across the electrodes reaches 'striking' voltage, which is usually around 100V, the gas ionizes and starts to conduct, in this state it looks electrically like a low value resistor and will conduct considerable current if allowed to do so. That's why the high value resistor is used in an AC indicator application, without it the neon would explode violently.
If you put one from the antenna to ground it will do nothing unless the antenna voltage reaches 100V or so and at that point, it will flash and safely (I hope!) short the current safely to ground. The 10K resistor I suggested will limit the current toward the IC to a level the two diodes can safely carry and dump either to ground or the supply rail.
Nichrome isn't a good material for making resistors. It has a high temperature coefficient, meaning it's value changes significantly with temperature. You can use it but to work out the current using I = V/R you need to know what R actually is and while hot the value will be difficult to measure. The current will be in pulses anyway which makes it even more complicated to measure, that's why I suggested an oscilloscope which lets you see and measure the peaks and dips of curent in real time.
Brian.
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