Hello avidestroyer,
Look for my answer to your question before.
how it retain one bit data?
Look for the circuit.
If the left transistor (T
1) is close the output A
1 has high level "1".
Through the base resistor (18kΩ) the left transistor (T
2) is hold open, because A
1 is "1" and T
2 gets positive base voltage. So the output A
2 has low level "0". Through the base resistor of T
1 the base is hold on low level and hold the transistor close.
If you put the input E
20 to ground or give a negative pulse, T
2 close and A
2 changes to "1". At the same time the base of T
1 gets also high level from the base resistor. A
1 changes to "0". Now the base of T
2 is hold on low level by A
1. After the input E
20 is not more grounded or the negative pulse is gone, this condition is hold until E
10 is grounded or gets a negative pulse.
The conditions at the outputs changes, when a negative pulse arrive at the opposite input.
Regards
Rainer