It's no impedance at all."gds" is common-source output impedance
a.zar said:How about if transistor works in subthreshold region? How much would be the output resistance of the trarnsitor?
Thanks.
Correcta.zar said:Thanks erikl,
So assuming Vth is thermal voltage,
Yesa.zar said:are you saying that the ro is 1/gm?
/1/ Behzad Razavi: "Design of Analog CMOS Integrated Circuits", McGraw-Hill Int.Ed. 2001 Chap. 2.3 p. 27/28 . The slope factor "n" here is printed as (grec) "zeta"a.zar said:Is there any reference for this equation?
To a first approximation, yes; Exact: n = 1 + (Gamma(b) / 2*sqrt(Psi(s))) /2/ eq. (3.34)a.zar said:Is n=1+Cdepletion/Cox?
S. /2/ Chap. 3.5.1 eq. (3.31)..(3.37) and Fig. 3.7 & 3.8 (p. 21 ff)a.zar said:How does n depend on Vds?
peterlau1984 said:Dear all,
I found the statement in cadence document that "ron" is on-resistance, while "gds" is common-source output impedance. Both of them are operating point parameters. What is the difference between ron and 1/gds?
Furthermore, we usually caculate with the parameter "ro" during design, which is equivalent with "ro", "ron" or "1/gds"?
Thanks!
If rout=1/gm then gm.rout=1 . gain=gm*Rloada.zar said:Thanks a lot.
Added after 2 hours 52 minutes:
Hi again erikl, just another quick question: With rout=1/gm, what would be the gain of the transistor? Is the equation gain=gm.rout still valid?
Thanks.
I think ro=(1/gds) is the small signal (differential) output impedance, whereas ron is the DC output resistance, as sanjeeb stated above.... ro=(1/gds) and ron is from device parameter, clearly both are not same!
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