what are effects and consequences zero power factor

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muhammad11

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What will occur to inductive loads like motors and resistive load like bulb if power factor becomes zero
 

A poor power factor in homes does not cost more because homes are billed for the actual power used. A poor power factor in industry costs a lot more than if the power factor is reduced.

Electrical gadgets are sold "to reduce your home electricity cost" but they are simply a capacitor that is not calculated properly to reduce the power factor. A poor power factor in a home does not cost more anyway.

The power factor of an inductive motor is reduced and can be zero if a capacitor is properly calculated for it and if the motor's load and speed is not changed. A resistive load already has a zero power factor.
 

you mean 1 power factor not zero, right ?
 

If the power factor is zero , then the load has NO resistive part. A lamp bulb is only resistive. A motor is slightly resistive when off load and highly resistive on load. A zero power factor means you are using either a capacitor or an inductor as a load. The power generators do not like a poor power factor, so there are regulations to make sure that electrical apparatus has a power factor greater then .8 .
Frank
 

No Power goes to the Load ....
cos Phi=0
P=U*I*cos Phi =0
.............
I think It is impossible state ....
 

No exactly zero PF but nearly zero(you cant have a pure L or C, the R will come in any way)...
--> High current form the line
--> Higher power loss
 

Power factor can be described in the frequency domain. Recall that the power measurements are the same for the integrals of voltage and current in either time or frequency. For frequency, two things could make the power factor 0. The first is the common definition -- that phase = +-90d between voltage and current. The second occurs when voltage and current occur at different frequencies. This can be "harmonic power factor", or any number of different descriptions.

For example, a DC source that connects to an AC current sink. The average power is 0, but measuring voltage and current will give non-zero RMS values and thus some apparent power. The source/load isn't inductive or capacitive as there is no meaningful phase that can be measured. Another common example would be the diode-capacitor AC-DC converters. These draw current in large bursts of current at the peak of the voltage waveform. The peak is near the center of the voltage waveform, so it will be mostly resistive. But the RMS current is very high. The power factor is low despite the apparent resistive load because the current waveform has lots of energy in frequencies other than the fundamental

For the original question, inductive loads at 0 PF have no resistance. They would simply charge and discharge each cycle with current exactly 90deg different than voltage. For a 0 PF resistive load, you could have something like the diode-capacitor example, but to the extreme -- where current is very short, very high bursts only at the peak of the sine wave. The load will be resistive, but will approach a 0 PF as the pulse width is decreased. (in this case, V*I has a positive average, and V*I is never negative, so energy is only transfered to the load.)
 

there are two ways in which your problem can be considered
1)you are drawing power such that power factor is zero that means u will be charged a lot for waste power.

2) if the generating station itself provides you power with zero factor which means:
consider you connect a generator(pure inductor) at your house and try to draw power from it what will happen it's all useless or reactive power which u will be drawing even of no use to connect the load.
so same thing is now consider the generating station with 0 pf means u can imagine that we will never get real power from the station(considering the generator at station to be pure inductor ) got it??
 

Please senior members guide us.

When power factor is zero its mean that there will be only reactive component and resistive component will be zero.So in my thinking ,bulb willnot turn on because it is a resistive load.What will occur for motors??????
Any expert should comment please
 

then perhaps it is not a generating station.
Your situation is as if two motors connected in parallel one is the generating station & other is your load i.e motor.
 

Please senior members guide us.

So in my thinking ,bulb will not turn on because it is a resistive load.What will occur for motors??????
Any expert should comment please

The bulb will turn on since PF for a resistive load is 1.

Your motor is not a pure inductive load.
The winding resistance makes it a R-L Load.

Hence your motor cannot have a 0 PF. It will have a PF < 1 and will be lagging in nature..But NOT 0.
 

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