[SOLVED] way to approach the equation

[kashyapa1]

Hi,
the equation to be solved is y= a(x)^m + b(x)^n.
Where a,b,m and n are all constants.
I have a set of 250 values each for x and its corresponding y value.
I thought of assuming m>n and hence for lower values of x the second term on RHS dominates and for higher values of x the first term on rhs dominates because the values are like that.
Help me a way to solve this
Thank you for skimming the question.

 

[Ratch]

kashyapa1,

the equation to be solved is y= a(x)^m + b(x)^n.
Where a,b,m and n are all constants.

If a is a constant, then why does it vary according to x, a(x)?

Ratch

 

[kashyapa1]

sorry it is not a(x) but instead a*(x)^n

 

[Ratch]

kashyapa1,

the equation to be solved is y= a(x)^m + b(x)^n.
Where a,b,m and n are all constants.
I have a set of 250 values each for x and its corresponding y value.
I thought of assuming m>n and hence for lower values of x the second term on RHS dominates and for higher values of x the first term on rhs dominates because the values are like that.
Help me a way to solve this

So, what is the question? You have an equation, a set of four constants, a set of 250 values for "x", and a corresponding set of "y" values that supposedly satisfy the equation. What is the unknown to solve?

Ratch

 

[albbg]

If you have to estimate a,b, m and n from 250 (x,y) pairs, I think you can use a best-fit tool like "curve expert"