Volume loss density in HFSS?

Status
Not open for further replies.
D

dopplerjeff5000

Newbie level 5
Joined
Dec 11, 2012
Messages
9
Helped
2
Reputation
4
Reaction score
1
Trophy points
1,283
Activity points
1,343
Hello,

I see the volume loss density in HFSS is defined as...

ρ=Re[E•J+jωB•H]

Where does this come from? I suspect it comes out in the derivation of the Poynting vector, but I haven't seen this form in the derivations. If anyone has derived volume loss density in this form I'd be interested in seeing it.
 

Hi,

I'm bumping the thread because the matter remains unsolved. Derivation of volume loss density from Maxwell's equations yields ρ=σE, while HFSS shows it as in the original post. Any input on where the magnetic part comes from? Is it just the magnetic current component?
 

I thought I could bump my own post since it has not been answered and over 600 views. There is obviously interest in the topic. That said, I leave it up to you. Just let me know if you should delete it or if I should delete it.
 

I prefer to rate your post as additional question rather than not permitted bumping...

- - - Updated - - -

I meant it's O.K to add a question, and I think you did.
 
dopplerjeff5000 said:
Where does this come from? I suspect it comes out in the derivation of the Poynting vector, but I haven't seen this form in the derivations. If anyone has derived volume loss density in this form I'd be interested in seeing it.
Click to expand...

I think your guess is correct.

The real part of the time-dependant Poynting Vector is

p(t) = Re{E.J + H.M}, which since M = jwuH is equal to Re{E.J + jwuH.H} which is Re{E.J + jwB.H}
 
PlanarMetamaterials said:
I think your guess is correct.

The real part of the time-dependant Poynting Vector is

p(t) = Re{E.J + H.M}, which since M = jwuH is equal to Re{E.J + jwuH.H} which is Re{E.J + jwB.H}
Click to expand...

It is encouraging to see your answer! Taking it a step further, I know that jwB•H can be interpreted as the curl of E•H. But is this quantity significant? The J•E term can be interpreted as power lost to heating, but what about the other term?
 

Remember that HFSS deals with magnetic sources, or if you prefer, magnetic conductivity or magnetic charges. These quantities are realized in places such as Perfectly Matched Layers (PMLs) or the Magnetic Current Source Excitation. While these don't *technically* exist in real life, (and therefore we say M = 0), HFSS uses these values as "shortcuts", and therefore needs to take them into account.
 


I also want to know where the equation comes from? Do you have the references? which papers or books?
 

Status
Not open for further replies.

Similar threads

Menu
Log in
Register
Cookies are required to use this site. You must accept them to continue using the site. Learn more…