verilog program of reconfigurable johnson counter

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jincyjohnson

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can you give me the verilog code of reconfigurable johnson counter.ie; there are two external inputs-mode and init.when mode=0,it works as a johnson counter.when mde=1 & init=0, it should reset. when mode=1 & init=1,it works as a ring counter.actually i initialize all the flip flops output first.but only johnson counter and reset works, ring counter doen't work.in ring counter mode the output is all zeros .can u give me the verlog code
 

How about you put in some time and try it first. When you're stuck show your code + explain where you are stuck.
 

here i attach code and block diagram.in ring counter mode, output are zeros
 

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  • johnson cntr.pdf
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  • johnson counter.pdf
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Okay, that's a good start. Do you have a testbench + testbench results to go with that? Oh and it's probably easier if you post the code using [code] tags (instead of attaching a pdf with verilog code in it). Also see this one for a quick description:
 

Code Verilog - [expand]
1

[syntax=verilog]
[/syntax]
Code: 
module johnson(clk,rst,init,rjmode,q);
input clk,rst,rjmode,init;
parameter n=5;
output [n-1:0]q;
reg [n-1:0]q_i;
reg temp;
integer I;
always @(posedge clk or negedge rst)
begin
if(!rst)
for(I=0; I<=n-1; I=I+1)
q_i <= 1'b0;
else
begin

if (!rjmode)

temp = ~q_i[n-1];
else 
temp = (q_i[n-1]) &&(init);

for(I=n-1;I>=1; I=I-1)
begin
q_i[I] = q_i[I-1];
end
q_i[0] = temp;

end
end
assign q = q_i;
endmodule
 

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can you give me the test bench code for the program.how can we write test bench for a program with 'for loop'
 

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