Verilog Error: expecting 'endmodule', found 'for'

Status
Not open for further replies.

Saptarshi1992

Newbie level 1
Joined
Apr 22, 2014
Messages
1
Helped
0
Reputation
0
Reaction score
0
Trophy points
1
Visit site
Activity points
37

Code Verilog - [expand]
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
132
133
134
135
136
137
138
139
140
141
142
143
144
145
146
147
148
149
150
151
152
153
154
155
156
157
158
159
160
161
162
163
164
165
166
167
168
169
170
171
172
173
174
175
176
module approximateMultiplier(
    input [7:0] a,b,
    output [15:0] s
    );
 
    wire [15:0] p0, p1, p2, p3 ,p4 ,p5, p6, p7;
    wire [15:0] q0, q1, q2, q3;
    wire [15:0] r0, r1;
    wire [15:0] e1, e2, e3, e4, e5, e6, e7;
    wire [15:0] s_, e_, E;
    wire [4:0]c;
    
    supply0 zero;
    
    //generating the partial products p0-p7
    assign p0 = b[0]*a;
    
    assign p1 = b[1]*a;
    assign p1 = p1<<1;
    
    assign p2 = b[2]*a;
    assign p2 = p2<<2;
    
    assign p3 = b[3]*a;
    assign p3 = p3<<3;
    
    assign p4 = b[4]*a;
    assign p4 = p4<<4;
    
    assign p5 = b[5]*a;
    assign p5 = p5<<5;
    
    assign p6 = b[6]*a;
    assign p6 = p6<<6;
    
    assign p7 = b[7]*a;
    assign p7 = p7<<7;
    
    integer i;  //loop variable
    //Zero pad the remaining bits int the left side of p0-p7
    assign p0[15:8] = 8'b0000_0000;
    assign p1[15:9] = 7'b0000_000;
    assign p2[15:10] = 6'b0000_00;
    assign p3[15:11] = 5'b0000_0;
    assign p4[15:12] = 4'b0000;
    assign p5[15:13] = 3'b000;
    assign p6[15:14] = 2'b00;
    assign p7[15] = 1'b0;
    
    
    //Now we have p0-p7. Genarate q0-q3
    for(i=0; i<=8; i=i+1)                            //ERROR IN THIS LINE
    begin
        if(i==0)    //the 0-th bit will not have any (i-1)-th term. Hence, seperately calculated.
        begin
            //assigning the values to the 0-th bits of q0-q3
            assign q0[i] = p0[i]^p1[i];
            assign e1[0] = 0;
            
            assign q1[i] = 0;
            assign q1[i+1] = 0;
            assign q1[i+2] = p2[i+2]^p3[i+2];
            assign e2[i] = 0;
            assign e2[i+1] = 0;
            
            assign q2[i] = 0;
            assign q2[i+1] = 0;
            assign q2[i+2] = 0;
            assign q2[i+3] = 0;
            assign q2[i+4] = p4[i+4]^p5[i+4];
            assign e3[i] = 0;
            assign e3[i+1] = 0;
            assign e3[i+2] = 0;
            assign e3[i+3] = 0;
            
            assign q3[i] = 0;
            assign q3[i+1] = 0;
            assign q3[i+2] = 0;
            assign q3[i+3] = 0;
            assign q3[i+4] = 0;
            assign q3[i+5] = 0;
            assign q3[i+6] = p6[i+6]^p7[i+6];
            assign e4[0] = 0;
            assign e4[i+1] = 0;
            assign e4[i+2] = 0;
            assign e4[i+3] = 0;
            assign e4[i+4] = 0;
            assign e4[i+5] = 0;
            
            //assigning the values to the 0-th bits of r0 and r1
            assign r0[i] = q0[i]^q1[i];
            assign e5[0] = 0;
            
            assign r1[i] = 0;
            assign r1[i+1] = 0;
            assign r1[i+2] = 0;
            assign r1[i+3] = 0;
            assign r1[i+4] = q2[i+4]^q3[i+4];
            assign e6[i] = 0;
            assign e6[i+1] = 0;
            assign e6[i+2] = 0;
            assign e6[i+3] = 0;
            
            //assigning the values to the 0-th bits of s_
            assign s_[i] = r0[i]^r1[i];
            assign e7[0] = 0;
        end
        
        else    //fill other bits
        begin
            assign q0[i] = (p0[i]^p1[i]) | (p0[i-1] & p1[i-1]);
            assign e1[i] = (p0[i]^p1[i]) & p0[i-1] & p1[i-1];
            
            assign q1[i+2] = (p2[i+2]^p3[i+2]) | (p2[i+1] & p3[i+1]);
            assign e2[i+2] = (p2[i+2]^p3[i+2]) & p2[i+1] & p3[i+1];
            
            assign q2[i+4] = (p4[i+4]^p5[i+4]) | (p4[i+3] & p1[i+3]);
            assign e3[i+4] = (p4[i+4]^p5[i+4]) & p4[i+3] & p1[i+3];
            
            assign q3[i+6] = (p6[i+6]^p1[i+6]) | (p0[i+5] & p1[i+5]);
            assign e4[i+6] = (p6[i+6]^p1[i+6]) & (p0[i+5] & p1[i+5]);
        end
    end
    
    //Zero pad the remaining bits int the left side of q0-q3
    for(i=9; i<=15; i=i+1)
    begin
        assign q0[i] = 0;
        assign q1[i+2] = 0;
        assign q2[i+4] = 0;
        assign q3[i+6] = 0;
    end
    
    
    
    //Now we have q0-q3. Generate r0 and r1
    for(i=1; i<=10; i=i+1)
    begin
        assign r0[i] = (q0[i]^q1[i]) | (q0[i-1] & q1[i-1]);
        assign e5[i] = (q0[i]^q1[i]) & q0[i-1] & q1[i-1];
        
        assign r1[i+4] = (q2[i]^q3[i]) | (q2[i-1] & q3[i-1]);
        assign e6[i+4] = (q2[i]^q3[i]) & q2[i-1] & q3[i-1];
    end
    
    //Zero pad the remaining bits int the left side of r0 and r1
    for(i=11; i<=15; i=i+1)
    begin
        assign r0[i] = 0;
        assign r1[i+4] = 0;
    end
    
    
    
    //Now we have r0 and r1. Genarate s_
    for(i=1; i<=15; i=i+1)
    begin
        assign s_[i] = (r0[i]^r1[i]) | (r0[i-1] & r1[i-1]);
        assign e7[i] = (r0[i]^r1[i]) & r[i-1] & r1[i-1];
    end
    
    
    //Now we have s_. Accumlate e_ = e3|e4|e6|e7
    assign e_ = e3|e4|e6|e7;
    //mask all other bits of e_ and keep 11-14 alive only. Save this error part in E
    assign mask = 16'h7800;
    assign E = mask & e_;
    
    //we have s_ and accumulated error E. Add them to get the inaccurate result.
    assign s = s_;
    fullAdder F1(s_[11], E[11], zero, s[11], c[0]);
    fullAdder F2(s_[12], E[12], c[0], s[12], c[1]);
    fullAdder F3(s_[13], E[13], c[1], s[13], c[2]);
    fullAdder F4(s_[14], E[14], c[2], s[14], c[3]);
    fullAdder F5(s_[15], c[3], zero, s[15], c[4]);
endmodule



ERROR:HDLCompilers:26 - "approximateMultiplier.v" line 72 expecting 'endmodule', found 'for'

Not only in the loop which i have marked as error, but also, in the other for loop used, i am getting this error. Can anyone plz help me solve the problem?
Thanking in Advance
 
Last edited by a moderator:

Code:
generate  for (i=0; i<16; i=i+1)
  begin : toto_name
    <code>
  end
endgenerate
 

Besides what rca pointed out, you have many more problems with this code.

You can't reassign a wire multiple times, only the last assign is valid. You're writing this Verilog code as if it behaves like a software program, which Verilog isn't, Verilog is a hardware description language and what you've written can't be represented in hardware. This entire block of code is a large combinational circuit, which will be very slow.

You should have only one assignment to p1 not three like here.

Code Verilog - [expand]
1
2
3
4
5
6
7
8
// you wrote three assignments that won't actually work correctly
// based on your software implementation.
assign p1 = b[1]*a;
assign p1 = p1<<1;
assign p1[15:9] = 7'b0000_000;
 
// you should have written a single assignment like this:
assign p1 = {7'b0, b[1]*a, 1'b0};


The multiplication will result in a large combinational logic cone, which will be very slow. As there is no clocks in the module I'm not at all sure what you intend to do with this code.

You're for loop suffers from multiple reassignments, as you are using it as you would a for loop in say C. Unlike software languages, wire declarations are not variables that store values. So once the for loop finishes only the last assignment to the wires that occurred is valid (i.e. all the earlier assignments are thrown away). A Verilog for loop also gets unrolled and becomes parallel logic, which is different than the way software handles for loops.

I'm sure there are other issues, but until you understand you are trying to describe hardware, not a software program, you're code is not going to be usable.

Regards
 

Status
Not open for further replies.
Cookies are required to use this site. You must accept them to continue using the site. Learn more…