constant amplitudeHi,
so what does "same amplitide" mean?
* constant amplitude?
* or with increasing frequency you also want increasing amplitude?
For that latter:
* either use a "multiplier circuit"
* or use a "differentiator". May be a passive high pass filter with very low cut off freqency.
Klaus
this is not a true VCO solution.
You may control the frequency by wiring the analog signal to a microcontroller that cantrols the DDC chip.
Counter question: If a diesel engine in a vehicle provides power to charge batteries .. and these batteries are used for electro-motors that move a car ... is it still a true electric car? Or a true diesel car?if I dont tell you whats in between then can it be a "true" VCO ?
Re-read my sentence ... does it support your solution, or did I counter-argument?My example the DelSig controls the DDS. Although in the part is a CPU totally capable
of controlling the DDS and messing up my "false" VCO.
Examples here : https://en.wikipedia.org/wiki/Barkhausen_stability_criterion # 5 foot noteHi,
Wow. It´s not the first time you get triggered when I reply to a post of you. So, what´s the problem?
I even wrote that I thought about the same as you ... and even explained the difficulties of a VCO (VCO as described by Wikipedia, or AnalogDevices, or whatever result you get on an internet search for "what is a VCO"). .. and I even explained the benefit of a DDS solution.
So even if I positively validate your post ... you´re getting emotional ... and forget that this is a technical discussion. And different opinions are just normal (And non_different opinions should be allowed, too. Or don´t you agree?).
Counter question: If a diesel engine in a vehicle provides power to charge batteries .. and these batteries are used for electro-motors that move a car ... is it still a true electric car? Or a true diesel car?
[IMHO: usually it is called a "hybrid solution" .... and "hybrid" is nothing negative. It just combines "two technologies" .. usually to a solution with new features]
You mentioned Barkhausen and provided a link to a forum thread.
Did you read the thread?
One sentence says: "the original Barkhausen criterion was (and is) a necessary criterion only. That means: When a circuit oscillates it will fulfill this criterion."
So for the OP .. what´s the key-information from this link? Wrong/flase/good/bad.....?
On my "analog solutions ..." statement you argumented that "The Barkhausen condition not the only way to create oscillators". Fair enough. Can you provide an example? You underline your knowledge .. and I´m open to learn.
Re-read my sentence ... does it support your solution, or did I counter-argument?
I´m not familier with this IDE. So forgive me that I can´t see how the DelSig controls the DDS.
Indeed I don´t need to understand ... you addressed the solution to the OP, so it´s more important that the OP understands.
Don´t know what you mean with "messed up" at all.
Klaus
this is not a true VCO solution.
Huh, and I thought that if I apply a V to a pin and get a changing freq sine with stable
amplitude out on another pin it was a "true" VCO. So now I have to call it a "false" VCO
solution......
So Vin = Freq out, and if I dont tell you whats in between then can it be a "true" VCO ?
I´m not familier with this IDE. So forgive me that I can´t see how the DelSig controls the DDS.
I explained it, I gave an example, I talked about the internet search and it's hits like Wikipedia, AnalogDevices... What else do you need?While you are at it can you tell me what a "true" VCO is, never learned that....., what
differentiates it from a non true VCO ?
Call me dumb ... but I can not find a proove for your "The Barkhausen condition not the only way to create oscillators".Examples here : https://en.wikipedia.org/wiki/Barkhausen_stability_criterion # 5 foot note
True. So far. I've used similar circuits for tracking mains frequency, this means for a rather narrow frequency range. Where it works great, btw.This digital method yields unchanging amplitude.
While you are at it can you tell me what a "true" VCO is, never learned that....., what
differentiates it from a non true VCO ?
I can not find a proove that there are analog oscillators that don't satisfy Barkhausen.
I have no clue what you refer to. I can find nothing about "homework", "attach...", "page 15". WTH are you talking about?Barkhausen, last time on the homework, page 15 on....attached
... already given.Your answer is ?
Thanks, this really is useful information. Never heard about it, learned something new.As pointed out earlier in references Tunnel Diode oscillator comes to mind.
ConclusionBarkhausen Criterion and Another Necessary Condition for Steady State Oscillations Existence
So the Barkhausen criterion is fulfilled (for A=1.5 in the case of MW oscillator and for A=4 in the case of DT oscillator if m=1) but these circuits cannot oscillate. This fact was confirmed not only by means of the linear analysis solving appropriated CEs and their root locus diagrams but nonlinear analysis and experiments as well [15]. Our investigation of these feedback circuits leads us to assume that the demand to
0/ 0 < ω dd ωϕ
could be taken as another necessary condition for steady state oscillation existence and understood as a supplement of the Barkhausen criterion
oscillations of an electronic circuit. Barkhausen did not ”open the loop” ! Oscillators may be classified into three groups based on the Barkhausen Observation. A Wien bridge oscillator with an almost linear inverting amplifier and a nonlinear passive amplitude and frequency determining feed-back circuit is investigated by means of the time-varying linear approach (”frozen eigenvalues”)
Analog solution:
Analog solutions all go back to the oscillation requirement for 180° phase shift and gain of 1.
But this is not simple to a achieve.
But what do you (or should we) focus on?So post #7 (below snippet) is not sufficient (which for most of us we learned the below inaccurate criteria in school),
eg that we now know Barkhausen is not complete, not sufficient design criteria.
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