[SOLVED] uVision4 MDK LPC2138 ADC Burst mode not generating interrupt

Status
Not open for further replies.

prerak

Newbie level 4
Joined
Dec 16, 2011
Messages
5
Helped
0
Reputation
0
Reaction score
0
Trophy points
1,281
Visit site
Activity points
1,320
Dear Experts,

I am trying to execute LPC2138 ADC in burst mode with interrupt, and here is my code:
Code:
int data0, data1;
__irq void intAdc(void){
	int ad = AD0DR;
	
	int channel = (ad >> 24) & 0x7;
//	AD0CR &= ~(0x1 << 16);
//	AD0CR &= ~(0x1 << 21);
	if(channel == 0){
		data0 = (ad >> 6) & 0x3ff;
	} else if(channel == 1){
		data1 = (ad >> 6) & 0x3ff;
	}
	//AD0CR |= 0X1 << 24;
	//AD0CR = AD0CR;
	
//	AD0CR |= 0x1 << 16;			// Burst
//	AD0CR |= 0X1 << 21;			// operational
	AD0DR &= ~(0x1 << 31);
	VICVectAddr0 = 0x0;
}

void initAdc(void){
	// enable ad0.0 and ad0.1 in burst mode
	// the values should be read by the above interrupt
//	AD0CR = 0x0;
//	AD0CR |= 0x3;				// 0 and 1
//	AD0CR |= 13 << 8;			// @4 MHz
//	AD0CR |= 0x1 << 16;			// Burst
//	AD0CR |= 0x0 << 17;			// clks = 0
//	AD0CR |= 0X0 << 20;			// reserved
//	AD0CR |= 0X1 << 21;			// operational
//	AD0CR |= 0X0 << 22;			
//	AD0CR |= 0X1 << 24;
//	AD0CR |= 0X0 << 27;
	
	AD0CR = 0x00211D03;

	VICVectAddr2 = (unsigned int) intAdc;
	VICVectCntl2 = 0x20 | 18;
	VICIntEnable |= 0x1 << 18;
	
//	PCONP |= 0x00001000;
//	AD0INTEN = 0xff;
	//ADGSR |= 0x1 << 16;
}

The code causes the interrupt to fire once, and then never again.
The DONE and the OVERRUN bits are asserted since the interrupt is not called and AD0DR is no longer read.
What am I missing here?
Your help is greatly appreciated!
Thanks,
Prerak
 

I have found the problem.
At the end of the ISR, I was stupidly doing VICVectAddr0 = 0 instead of VICVectAddr = 0.
After correcting that, it works fine.
 

Status
Not open for further replies.

Similar threads

Cookies are required to use this site. You must accept them to continue using the site. Learn more…