Jul 25, 2012 #1 thebadtall Full Member level 6 Joined May 17, 2012 Messages 339 Helped 12 Reputation 24 Reaction score 12 Trophy points 1,308 Location Hellas Activity points 3,605 Hello, I measured a typical lamp and is 100Ohm / 40W Can I use it as replacement of a high wattage resistor of same value ? Thank you
Hello, I measured a typical lamp and is 100Ohm / 40W Can I use it as replacement of a high wattage resistor of same value ? Thank you
Jul 25, 2012 #2 alexan_e Administrator Joined Mar 16, 2008 Messages 11,888 Helped 2,021 Reputation 4,158 Reaction score 2,031 Trophy points 1,393 Location Greece Activity points 64,371 The resistance when an incandescent bulb is cold is about 1/10 of the resistance when the lamp is on and the filament heated. A 100 ohm resistance would results in (220²)/100= 484W for 40v @220v the operating resistance is R= 220² / 40 = 1210 ohm
The resistance when an incandescent bulb is cold is about 1/10 of the resistance when the lamp is on and the filament heated. A 100 ohm resistance would results in (220²)/100= 484W for 40v @220v the operating resistance is R= 220² / 40 = 1210 ohm
Jul 26, 2012 #3 LvW Advanced Member level 6 Joined May 7, 2008 Messages 5,915 Helped 1,754 Reputation 3,514 Reaction score 1,366 Trophy points 1,393 Location Germany Activity points 40,555 Such a device can be used - for example - as a non-linear gain controlling element (with positive temperature coeff..) in harmonic oscillators. In fact, it was used by Mr. W.R. Hewlett in 1939 to stabilize the world's first WIEN oscillator.
Such a device can be used - for example - as a non-linear gain controlling element (with positive temperature coeff..) in harmonic oscillators. In fact, it was used by Mr. W.R. Hewlett in 1939 to stabilize the world's first WIEN oscillator.
Jul 26, 2012 #4 E Electro Builder Newbie level 6 Joined Jul 17, 2012 Messages 14 Helped 1 Reputation 2 Reaction score 1 Trophy points 1,283 Activity points 1,390 hai alexan hw u got that 1210ohm
Jul 26, 2012 #5 alexan_e Administrator Joined Mar 16, 2008 Messages 11,888 Helped 2,021 Reputation 4,158 Reaction score 2,031 Trophy points 1,393 Location Greece Activity points 64,371 P=V*I and I=V/R so you can write P= V * (V/R) = V²/R If you solve for R then R= V²/P V=220v P=40W R = 220²/40 = 48400/40 = 1210 ohm Alex
P=V*I and I=V/R so you can write P= V * (V/R) = V²/R If you solve for R then R= V²/P V=220v P=40W R = 220²/40 = 48400/40 = 1210 ohm Alex