boylesg
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The transformer input current (and respective inductor voltage drop) can't be determined from the transformer winding resistance. You ask for the no-load or loaded input current.
Do determine the transformer input voltage for known current, AC network calculation methods have to be applied (considering magnitude and phase).
A 3 mH inductor won't make much sense for current limiting purposes, according to a reactive impedance of about 1 ohm. How did you derive the number?
As you know, magnetron transformers are usually designed as stray field transformers, isn't it the case with this transformer?
Quite simple, if the transformer acts as a short circuit, the current can be calculated as I=V/XL, XL being the reactive impedance of the inductor, XL=2*pi*f*L.
You are asking about elementary AC circuit calculations. A good introduction is e.g. https://www.ibiblio.org/kuphaldt/electricCircuits/AC/index.html
To make a power inductor (either for AC or DC), it's not sufficient to achieve an inductance xx. The inductor must be also designed in a way that it doesn't saturate at the rated current. In case of iron core inductors, this is hardly possible without an air gap.
As another point, due to non-linear magnetizing characteristic, the inductance at higher current will be considerably different from the value measured with a LCR meter. See https://www.edaboard.com/threads/302652/
For the time being, I assume that your "twin windings" inductor is a current compensated common mode choke. It's saturation current in series circuit will be very low.
In saturation, the inductance will drop to a small fraction of the initial value, you should place a fuse to protect your circuit.
The saturation current can be calculated if you know the core data. My estimation is something around 100 mA for a common mode choke with the said data.
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