Thank you Richard!
I am new to this website and I am amazed at the quality of the information that is available here.
Let me make sure I completely understand your reply.
It appears that the component that I thought was the main contributor is only a minor contributor, and what I thought was the minor contributor is actually the main source of increased current.
1. In the npn, the primary source of increased conduction as T rises are the thermally generated carriers in the C-B depletion region.
2. These carriers, specifically the holes, are driven back into the base, and act as base current, forcing the npn into higher Ic conduction.
3. The Rb which will also rise with temp, limits a possible shunt path for these holes (a shunt path would prevent them from acting as base current)
This makes good sense to me now. Thank you so much. I now feel comfortable calling these high temp currents "leakage" currents.
We are looking at designing power amps that must survive at the high underground temps in the oil & gas industry. We are looking at increased reliability at 200 C.
The product is a hybrid. The front end can be an IC amplifier specifically designed for high temp. Honeywell has an SOI process and they claim a 5 year lifetime at 225 C. We can purchase that die. My concern is in the temperature performance of the output transistors. They are a Darlington pair and need to supply around 10A. A previous design with this output stage shows a resistor connecting base to emitter. This external B-E resistor is shown for both transistors (the pre-driver and the driver) in the Darlington pair. Before your reply, I had read of two reasons for the B-E resistor in the driver: first it is known as a turn-off resistor; next it provides a shunt path for leakage currents from the pre-driver so that those leakage currents don't go entirely into the base of the driver. To those reasons, I can now also add that the external R provides a shunt path for the above discussed thermally generated holes.
Here are two follow up questions:
1.The external B-E turn-off resistor. I will run a simulation, but I wanted to reply to you asap monday morning, so before running that sim, my thoughts on understanding the turn-off are as follows: in saturation the base is full of holes. The external resistor allows these holes to conduct out of the base. Is this correct? To verify this, I should see current flowing out of the base at turn-off. Without this shunting resistor, we have to wait for recombination in the base before the base is cleared of holes.
2. ok, so the increased diffusion currents in the E-B junction are not the main source of higher currents in the npn. But what about in the diode? For the diode, as I run Id vesus Vd sweeps (Vd > 0) with temp as a parameter, the currents are much larger, as T increases. Here, the only possible current is forward biased current, and they are sensitive to temp. It is for this reason that I thought the E-B conduction might be the dominant source in the npn. Not really a question here, but more an opportunity for further comment.
Thanks for the reference for furhter reading.
Best,
David