try to give the logic

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kad

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Give a very good method to count the number of ones in a 32 bit number. (caution: looping through testing each bit is not a solution).
 

What ? Is that an order?

I hope you don't expect anyone to "give" you a ready-made solution...

google for "parity"
 

not an order, just verbatim from the homework assignment - lol!
 

electronrancher said:
not an order, just verbatim from the homework assignment - lol!

Sure looks like a straight lift but cann't resist frm replying

let x be d no. not equal to zero

ans=1
while(x>2)
{
if( x%2!=0) {ans++; x--;}
x=x/2;
}

ans will give the no. of ones

TRY TO UNDERSTAND THE LOGIC AS THATS WHAT MATTERS
 

Hi all

On average there will be 16 - the most probable prediction every time.

Polymath
 

polymath said:
Hi all

On average there will be 16 - the most probable prediction every time.

Polymath

Why should ?
 


Why not? You have not defined your 32 bits as having any structure other than random.

Read about Statistics & Probability.
Noise - Long Comm. Transmissions and many data structures have equal 1s & 0s by chance or design.

yes .. no .. yes .. no ... Polymath
 

Well polymath I think here we r talking abt deterministic coding and not the random ones.
 

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