boylesg
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Columns are A -> G Rows are 21 -> 24 IB= column contains the formula =E21/C21 RB= column contains the formula =(B21-D21)/F21 They are based on the equations here: http://www.zen22142.zen.co.uk/Design/bjtsw.htm
As you can see the only way that I can come up wihe 150R value for the resistor on the base of the darlington transistor is if I assume an emitter current of 20A. But this can't be right because they have a 10A fuse and the instructions state that they are limiting the current to 5A. So does anyone have any clue how they have come up with a 150R value for this resistor? Am I using the correct forumulas in my table? If I work backwards with a more sensible emitter current of 5-8A, this yields a base current of between 10-30mA, depending on whether I use 24V or 12V, and this in turn yields base resistor of some where around 2.2k for the BC327 as per the schematic. For the BC327 I am using the equations in here: http://www.kpsec.freeuk.com/trancirc.htm#ic **broken link removed** Transistor in switch mode - calculate IB and required RB | ||||||||||||||||||||||||||||||||||
Transistor | Vin | hFE | VBE | IE | IB = | RB = | ||||||||||||||||||||||||||||
BU931P | 24.0000 | 300.0000 | 1.8000 | 5.0000 | 0.0267 | 832.5 | ||||||||||||||||||||||||||||
2SC5446 | 24.0000 | 8.0000 | 1.5000 | 5.0000 | 0.6250 | 36 | ||||||||||||||||||||||||||||
BU931P | 12.0000 | 300.0000 | 1.8000 | 20.0000 | 0.0667 | 153 |