ankitvirdi4
Member level 4
Hello,
I have designed a linear power supply using a step down transformer, bridge rectifier and a filter capacitor , there on it goes to a shunt regulator TL431 to generate 3V3.
Ratings: Transformer 6V 230mA at 230V AC Input.
Capacitor: 2200uF/16V
The load is a 16 Digit Seven Segment Display module with each segment drawing about 8-9 mA.
There are 8 CCs multiplexed so that at any instant only 1 CC is on which means it sinks about 130-145mA
While validating the supply my observation is that the secondary AC voltage waveform appears to be clamped sinewave instead of a pure sinewave. Because of this Vdc at lower auxillary supply (185VAC) is about 4.36 with a 400mV ripple thus 3V3 has a huge 300mV ripple across it if the secondary waveform were pure sine Vpp would have been higher thus Vdc would been higher enabling operation at rated voltage 185VAC considering 20% tolerance on the power supply of the product.
I have clearly mistaken somewhere, can somebody help by pointing it out.
I have designed a linear power supply using a step down transformer, bridge rectifier and a filter capacitor , there on it goes to a shunt regulator TL431 to generate 3V3.
Ratings: Transformer 6V 230mA at 230V AC Input.
Capacitor: 2200uF/16V
The load is a 16 Digit Seven Segment Display module with each segment drawing about 8-9 mA.
There are 8 CCs multiplexed so that at any instant only 1 CC is on which means it sinks about 130-145mA
While validating the supply my observation is that the secondary AC voltage waveform appears to be clamped sinewave instead of a pure sinewave. Because of this Vdc at lower auxillary supply (185VAC) is about 4.36 with a 400mV ripple thus 3V3 has a huge 300mV ripple across it if the secondary waveform were pure sine Vpp would have been higher thus Vdc would been higher enabling operation at rated voltage 185VAC considering 20% tolerance on the power supply of the product.
I have clearly mistaken somewhere, can somebody help by pointing it out.