Feb 13, 2024 #1 S sevenStarCola Newbie Joined Feb 12, 2024 Messages 1 Helped 0 Reputation 0 Reaction score 0 Trophy points 1 Activity points 12 In left circuit, I try use thevenin to change circuit for 6 ome. At first try I think total resistence is 3ome. But after try that I notice that's total ome is zero..! I guess because current soure is cutted(when get total resister), but not think clearly can you help me..?
In left circuit, I try use thevenin to change circuit for 6 ome. At first try I think total resistence is 3ome. But after try that I notice that's total ome is zero..! I guess because current soure is cutted(when get total resister), but not think clearly can you help me..?
Feb 13, 2024 #2 W wwfeldman Advanced Member level 4 Joined Jan 25, 2019 Messages 1,116 Helped 232 Reputation 463 Reaction score 302 Trophy points 83 Activity points 8,742 not quite sure what you are asking. nor do i follow what you wrote. 6 ohm in parallel with 3 ohm yields 2 ohm 2 ohms in parallel with a 2A source is 4 V Thevenin form is a 4V source with a 2 ohm series resistor shorted yields the 2A from Norton version Upvote 0 Downvote
not quite sure what you are asking. nor do i follow what you wrote. 6 ohm in parallel with 3 ohm yields 2 ohm 2 ohms in parallel with a 2A source is 4 V Thevenin form is a 4V source with a 2 ohm series resistor shorted yields the 2A from Norton version