In this case, you risk to overload the backup source. How do I know that produces 5V 300mA max standby 1.5 W, that is. But this solution can work.2-change in divider resistors network of tl431.
it cause 5vsb increase too. but 5v is useful for digital
3-adding some turns to 12v node in secondary of stand by transformer
I don't test it yet
some comments on your circuit:
In this case, you risk to overload the backup source. How do I know that produces 5V 300mA max standby 1.5 W, that is. But this solution can work
Microsim provide an additional source for TL494 buffer transformer. In your circuit voltage is limited by Zener diode ZD26, which works only when the spike exceed 24V relative to voltage on pin #12.
is it's mean that both of set point or feed back output voltage on each of inverting or non-inverting input must be in range of 0.5v to 3.5v?
No, you are confusing amplifier output voltage range with input common mode range, it's specified as -0.3 to Vcc-2 V. In many popular TL494 designs, e.g. one input pin is connected to 5V Vref
Too bold to answer. (Review forum rules).
Of course there are, but they don't mention questions all typed in bold letters. So I just express my private opinion about it. Emphasizing an important question might be useful, but what's the purpose of typing all questions in bold?I do not find any rule about the format of asking questions
but every tl94 requires startup supply. so their should be a auxillary supply.of 12v . but i cant understand how your smps works without startup
supply
It`s AT PS, see post #6but every tl94 requires startup supply. so their should be a auxillary supply.of 12v . but i cant understand how your smps works without startup
supply
How to compensate the loss of diode?
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