jamesbond939
Newbie level 4
This is a basic question.
From the square-law model:
Vdsat = Vgs - Vth
If Vth of a process increase, we'll need higher Vgs to turn the device on right? In other words the Vdsat will remain the same for different Vth?
Why do we say that when Vth of a process increase, the headroom will decrease?
From the square-law model:
Vdsat = Vgs - Vth
If Vth of a process increase, we'll need higher Vgs to turn the device on right? In other words the Vdsat will remain the same for different Vth?
Why do we say that when Vth of a process increase, the headroom will decrease?