Power input is standard definition of power.
viz : v^2 / R, or I^2 x R, or V x I etc.
Thus (for example) if the input impedance of your AGC block is 50 ohms, and the pk-pk input voltage is 100 mV, then the input power would be :
Vrms = 35.36 mV rms
and input power is V^2 / R = 2.5 uW
This translates into ~ -16 dBm input
Now your AGC graph shows that for a -16dBm input, the gain is roughly 5 dB.
Hence output power would be -16+5 = -11dBm
This reverse translates to 79.4 uW output.
If your load at output of AGC is again 50 ohm, then you will see a pk-pk voltage swing of around 178 mV.
(i think all my above calcs are correct. I leave the detailed workings to you)