Jun 24, 2012 #1 B baby_1 Advanced Member level 1 Joined Dec 3, 2010 Messages 415 Helped 1 Reputation 2 Reaction score 1 Trophy points 1,298 Activity points 4,277 Hello Could you help me to solve this problem? i want to find w
Jun 24, 2012 #2 H hakeen Full Member level 5 Joined Jun 16, 2005 Messages 240 Helped 44 Reputation 88 Reaction score 19 Trophy points 1,298 Activity points 2,783 Hello Baby_1 the answer is w=10000*sqrt(230). Hope helps. Cheers
Jun 24, 2012 #3 G godfreyl Advanced Member level 5 Joined Apr 18, 2012 Messages 1,974 Helped 632 Reputation 1,266 Reaction score 621 Trophy points 1,393 Activity points 12,772 By trial and error, w = about 154000 I have no idea how to calculate it. What's this for?
Jun 24, 2012 #4 Baas Rietrot Member level 5 Joined Jun 19, 2012 Messages 92 Helped 15 Reputation 30 Reaction score 15 Trophy points 1,298 Location South Africa Activity points 1,711 This looks like the start of a phase margin calculation. Usually trail and error or plot it in MATLAB and read it off or use MATLAB's solve functions.
This looks like the start of a phase margin calculation. Usually trail and error or plot it in MATLAB and read it off or use MATLAB's solve functions.
Jun 24, 2012 #5 G godfreyl Advanced Member level 5 Joined Apr 18, 2012 Messages 1,974 Helped 632 Reputation 1,266 Reaction score 621 Trophy points 1,393 Activity points 12,772 hakeen said: the answer is w=10000*sqrt(230). Click to expand... How did you work that out?:???: (I agree with the answer) - - - Updated - - - Baas Rietrot said: This looks like the start of a phase margin calculation. Click to expand... Oh, right - for poles at 10KHz, 100KHz and 200KHz. I'd just use a simulator (or spreadsheet), but I'd still be interested to hear how Hakeen did the calculation.
hakeen said: the answer is w=10000*sqrt(230). Click to expand... How did you work that out?:???: (I agree with the answer) - - - Updated - - - Baas Rietrot said: This looks like the start of a phase margin calculation. Click to expand... Oh, right - for poles at 10KHz, 100KHz and 200KHz. I'd just use a simulator (or spreadsheet), but I'd still be interested to hear how Hakeen did the calculation.
Jun 24, 2012 #6 Baas Rietrot Member level 5 Joined Jun 19, 2012 Messages 92 Helped 15 Reputation 30 Reaction score 15 Trophy points 1,298 Location South Africa Activity points 1,711 I would also want to know how hakeen did it, this might help to eliminate the tedious trail and error method. Please post master hakeen:smile:
I would also want to know how hakeen did it, this might help to eliminate the tedious trail and error method. Please post master hakeen:smile:
Jun 24, 2012 #7 B baby_1 Advanced Member level 1 Joined Dec 3, 2010 Messages 415 Helped 1 Reputation 2 Reaction score 1 Trophy points 1,298 Activity points 4,277 Hello hakeen it is completely right. could you write the answer completely ? how did you find it ? it has a formula to solve these equation ? - - - Updated - - - By trial and error, w = about 154000 I have no idea how to calculate it. What's this for? Click to expand... i want to calculate an amplifier G.M(Gain Margin) and P.M(Phase margin)
Hello hakeen it is completely right. could you write the answer completely ? how did you find it ? it has a formula to solve these equation ? - - - Updated - - - By trial and error, w = about 154000 I have no idea how to calculate it. What's this for? Click to expand... i want to calculate an amplifier G.M(Gain Margin) and P.M(Phase margin)
Jun 24, 2012 #8 H hakeen Full Member level 5 Joined Jun 16, 2005 Messages 240 Helped 44 Reputation 88 Reaction score 19 Trophy points 1,298 Activity points 2,783 Hello thanks for good posts, but I am not math-master. Anyway, for solution two important things 1)arctan x + arctan y = arctan ( (x+y)/(1-x*y)) 2)arctan(x) = -pi --> x=0 so think it is x=w/10^4 then [arctan(x)+arctan(x/10)]+arctan(x/20) = -pi so from 1&2 x= sqrt(230) and w= sqrt(230)*10^4 Hope helps. Cheers
Hello thanks for good posts, but I am not math-master. Anyway, for solution two important things 1)arctan x + arctan y = arctan ( (x+y)/(1-x*y)) 2)arctan(x) = -pi --> x=0 so think it is x=w/10^4 then [arctan(x)+arctan(x/10)]+arctan(x/20) = -pi so from 1&2 x= sqrt(230) and w= sqrt(230)*10^4 Hope helps. Cheers
Aug 1, 2012 #9 K karthick1987 Member level 2 Joined Jul 4, 2012 Messages 49 Helped 10 Reputation 20 Reaction score 10 Trophy points 1,288 Location Sydney, Australia Activity points 1,631 If you apply tan on both sides first tan( arctan(w/10^4) + arctan(w/10^5) +arctan(w/2*10^5) ) = 0 then simple use tan ( A + B +C ) = tanA*tanB*tanC/(1-(tanA*tanB)-(tanA*tanB*tanC)) formula Immediately you see that w = 0 is a solution or you get a cubic at the bottom w^3/(10^4*10^5*2*10^5)/(1-(w^2/10^4*10^5)-w^3/(10^4*10^5*2*10^5) hope it helps K
If you apply tan on both sides first tan( arctan(w/10^4) + arctan(w/10^5) +arctan(w/2*10^5) ) = 0 then simple use tan ( A + B +C ) = tanA*tanB*tanC/(1-(tanA*tanB)-(tanA*tanB*tanC)) formula Immediately you see that w = 0 is a solution or you get a cubic at the bottom w^3/(10^4*10^5*2*10^5)/(1-(w^2/10^4*10^5)-w^3/(10^4*10^5*2*10^5) hope it helps K